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satela [25.4K]
3 years ago
14

How to solve for x as a denominator in an inequality?

Mathematics
1 answer:
labwork [276]3 years ago
8 0
Examples :

2/x < 4 ....multiply both sides by x, cancelling it on the left side
2 < 4x ...now divide by 4
2/4 < x
1/2 < x

5/x + 7 > = 12
5/x > = 12 - 7
5/x > = 5 ....multiply by x, cancelling it on the left
5 > = 5x...divide by 5
5/5 > = x
1 > = x


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zlopas [31]
The answer is a BDEFG
7 0
3 years ago
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Please look at the attachment and answer my question :(
pshichka [43]

Answer:

  • The number at B is 10.6

Step-by-step explanation:

Let the number at B be x.

We know that distance between two points on the number line is the absolute value of the difference of numbers at those points.

Then distances representing the lengths of segments AB and BC are:

  • AB = x - 9
  • BC = 13 - x

We are given the ratio of segments:

  • AB/BC = 2/3

Substitute and solve for x:

  • (x - 9)/(13 - x) = 2/3
  • 3(x - 9) = 2(13 - x)
  • 3x - 27 = 26 - 2x
  • 3x + 2x = 26 + 27
  • 5x = 53
  • x = 53/5
  • x = 10.6

8 0
1 year ago
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5x + 3y = -3 <br><br> 2X - 3y = 24
gregori [183]

Answer:

Y=-5/3x-1

y=2/3x-8

If you are adding then it is:

7x=21

x=3

Step-by-step explanation:

5x+3y=-3

3y=-5x-3

y=-5/3-1

2x-3y=24

-3y=-2x+24

y=2/3x-8

5 0
3 years ago
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The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
The line plot shows the weights of ten eggs laid by one hen. What is the total weight in ounces of the four heaviest eggs?
Likurg_2 [28]
The four heaviest eggs are 2 ounces, 2 ounces, 2 1/4 ounce is, and 2 1/2 ounces. Add these together to total 8 3/4 ounces.

The four heaviest eggs have a sum of 8 3/4 ounces.
8 0
3 years ago
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