Recall your d = rt, distance = rate * time
so hmm, if say the speed rate of the wind is "w", when the plane is flying with the wind, is not really flying 325 mph, is really flying " 325 + w " fast.
now, when the plane is going against the wind, so-called upwind, is not really going 325 mph either, is really going " 325 - w " fast.
now, bear also in mind that, it took "t" hours to go one way, and it also took "t" hours to go the other way.
so.... let's check then
