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Evgesh-ka [11]
3 years ago
10

A plane can fly 325 mph in still air. If it can fly 190 downwind in the same amount of time it can fly 135 miles upwind, find th

e velocity of the wind?
Mathematics
1 answer:
wariber [46]3 years ago
3 0
Recall your d = rt, distance = rate * time

so hmm, if say the speed rate of the wind is "w", when the plane is flying with the wind, is not really flying 325 mph, is really flying " 325 + w " fast.

now, when the plane is going against the wind, so-called upwind, is not really going 325 mph either, is really going " 325 - w " fast.

now, bear also in mind that, it took "t" hours to go one way, and it also took "t" hours to go the other way.

so.... let's check then

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{with the wind}&190&325+w&t\\
\textit{against the wind}&135&325-w&t
\end{array}
\\\\\\
\begin{cases}
190=t(325+w)\implies \frac{190}{325+w}=\boxed{t}\\\end{cases}

\bf \cfrac{135}{325-w}=\cfrac{190}{325+w}\implies 135(325+w)=190(325-w)
\\\\\\
(135\cdot 325)+135w=(190\cdot 325)-190w
\\\\\\
135w+190w=(190\cdot 325)-(135\cdot 325)\impliedby \textit{some common factor}
\\\\\\
325w=325(190-135)\implies w=55
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What is the length and width of a 864 square feet
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The area doesn't tell you the dimensions. There are an infinite number of different answers, all with the same area but different dimensions.
Here are a few:
1 ft by 864 ft
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3 ft by 288 ft
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16 ft by 54 ft
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27 ft by 32 ft.

The area of each of these is 864 square feet.
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4 0
3 years ago
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Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

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3 years ago
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