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Evgesh-ka [11]
3 years ago
10

A plane can fly 325 mph in still air. If it can fly 190 downwind in the same amount of time it can fly 135 miles upwind, find th

e velocity of the wind?
Mathematics
1 answer:
wariber [46]3 years ago
3 0
Recall your d = rt, distance = rate * time

so hmm, if say the speed rate of the wind is "w", when the plane is flying with the wind, is not really flying 325 mph, is really flying " 325 + w " fast.

now, when the plane is going against the wind, so-called upwind, is not really going 325 mph either, is really going " 325 - w " fast.

now, bear also in mind that, it took "t" hours to go one way, and it also took "t" hours to go the other way.

so.... let's check then

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{with the wind}&190&325+w&t\\
\textit{against the wind}&135&325-w&t
\end{array}
\\\\\\
\begin{cases}
190=t(325+w)\implies \frac{190}{325+w}=\boxed{t}\\\end{cases}

\bf \cfrac{135}{325-w}=\cfrac{190}{325+w}\implies 135(325+w)=190(325-w)
\\\\\\
(135\cdot 325)+135w=(190\cdot 325)-190w
\\\\\\
135w+190w=(190\cdot 325)-(135\cdot 325)\impliedby \textit{some common factor}
\\\\\\
325w=325(190-135)\implies w=55
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Answer:

<u>Recursive:</u>

a_n=a_{(n-1)}+18\\ \\ a_1=82

<u>Explicit:</u>

a_n=64+18n

Explanation:

<u>1. Sequence:</u>

a_1=82\\ \\ a_2=82+18=100\\ \\ a_3=100+18=118\\ \\ a_4=118+18=136\\ \\ ...

<u>2. Recursive formula</u>

The recursive formula permits to calculate the value of the nth term in the sequence using the (n-1)th term in the sequence.

a_n=a_{(n-1)}+18\\ \\ a_1=82

<u>3. Explicit formula</u>

The explicit formula permits to calculate any value of a term in the sequence:

a_n=a_1+(n-1)d\\ \\ a_n=82+(n-1)18\\ \\ a_n=82+18n-18\\ \\ a_n=64+18n

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3 years ago
Natalia is moving into a new house. All together, her furniture weighs 3,204 pounds. If it takes 8 trucks to carry all of Natali
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D

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3 years ago
Which of the following statements are true?
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Answer:

B, C

Step-by-step explanation:

Consider all options:

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C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

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3 years ago
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Step-by-step explanation:

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<u>Since all the options have 1/20 as a coefficient, our function is:</u>

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

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Then DS has length ...

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and DE is twice that length, so ...

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__

24. DS is half the length of DE, so is ...

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_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
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