A plane can fly 325 mph in still air. If it can fly 190 downwind in the same amount of time it can fly 135 miles upwind, find th
1 answer:
Recall your d = rt, distance = rate * time
so hmm, if say the speed rate of the wind is "w", when the plane is flying with the wind, is not really flying 325 mph, is really flying " 325 + w " fast.
now, when the plane is going against the wind, so-called upwind, is not really going 325 mph either, is really going " 325 - w " fast.
now, bear also in mind that, it took "t" hours to go one way, and it also took "t" hours to go the other way.
so.... let's check then
so hmm, if say the speed rate of the wind is "w", when the plane is flying with the wind, is not really flying 325 mph, is really flying " 325 + w " fast.
now, when the plane is going against the wind, so-called upwind, is not really going 325 mph either, is really going " 325 - w " fast.
now, bear also in mind that, it took "t" hours to go one way, and it also took "t" hours to go the other way.
so.... let's check then
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Step-by-step explanation:
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Substitute,
Simplify,
Inverse operations,
Take a factor from out of the square root. Remember that a number times itself under the radical is equal to the number. This can be simply stated as the following: (),