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dimaraw [331]
3 years ago
7

Which of the following statements is an example of climate?

Physics
1 answer:
Hoochie [10]3 years ago
8 0
D is the correct answer on that
You might be interested in
A current of 1.75 A flows through a 55.4 Ω resistor for 9.5 min. How much heat was generated by the resistor? Answer in units of
kirill115 [55]

Answer:

9.67\times 10^4 J

Explanation:

We are given that

Current=I=1.75 A

Resistance =R=55.4 ohm

Time=t=9.5 min=9.5\times 60=570 s

1 min=60 s

We have to find the heat generated by the resistor.

We know that

Heat=E=I^2Rt

Using the formula

Heat,E=(1.75)^2\times 55.4\times 570=9.67\times 10^{4} J

Hence, the heat generated by the resistor =9.67\times 10^4 J

6 0
3 years ago
What force is required to give an object with mass 125 kg an acceleration of 3
stiks02 [169]
The answer is B

Using the equation, F=MA, we can determine that...
(125kg) (3m/s^2) = 375N
7 0
4 years ago
Explain how the magnitude of the gravitational force between the earth and the sun changes as the earth moves from position 'A'
Lina20 [59]

Answer:

Explanation:

We are not told where A and B are, but I'll assume that they are two points on the orbit of earth about the sun.

As that orbit is an ellipse, the two points likely do not have the same distance between the earth and sun.

As gravity varies with the inverse of the square of the distance (F = GMm/d²), the force at the closer distance will be greater than the force at the longer distance.

4 0
3 years ago
an object is 40M below the surface of sea water of density 1020 kg/m3 calculate the pressure difference
olga nikolaevna [1]

Answer:

P = 400248 [Pa]

Explanation:

We can calculate the hydrostatic pressure exerted by a column of liquid by means of the following equation.

P=Ro*g*h

where:

Ro = density = 1020 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = depth = 40 [m]

Therefore:

P=1020*9.81*40\\P=400248 [Pa]

8 0
3 years ago
Wiley Coyote has missed the elusive road runner once again. This time, he leaves the edge of the cliff at 52.4 m/s with a purely
Morgarella [4.7K]

Answer:

<h2>280.86 m</h2>

Explanation:

Range is defined as the distance covered in the horizontal direction. In projectile, range is expressed as x = vt where;

x is the range

v is the velocity of the runner

t is the time taken

Before we can get the range though, we need to find the time taken t using the relationship S = ut + 1/2gt²

if u = 0

S = 1/2gt²

2S = gt²

t² = 2S/g

t = √2S/g

t = √2(141)/9.8

t = √282/9.8

t = 5.36secs

The range x = 52.4*5.36

x =280.86 m

Hence, the coyort lies approximately 280.86 m from the base of the cliff

3 0
3 years ago
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