Question

What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged particle as it travels through water (which has an index of refraction of n

Answer 1

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   $v_w = 2.256 *10^{8} \ m/s$

B

  $v_e = 2.21 *10^{8} \ m/s$

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  $n_w = 1.33$

      The  refractive  index of ethanol is  $n_e = 1.36$

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       $v_w = \frac{c}{n_w }$

Where  c is the speed of light with value  $c = 3.0 *10^{8} \ m/s$

       $v_w = \frac{3.0 *10^{8}}{1.33 }$

       $v_w = 2.256 *10^{8} \ m/s$

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            $v_e = \frac{ c}{n_e }$

  =>       $v_e = \frac{3.0 *10^{8}}{1.36 }$

=>          $v_e = 2.21 *10^{8} \ m/s$