Answer:
Case 1: <u>Pushing</u> Diagram 1
Leaning over and Pushing the heavy box from the floor, the push will be divided in to two parts, one is horizontal that can help the box move, and one is vertically downwards, which increases the downward force of the heavy object (an addition to the gravity) and thus increases friction, making it very hard to push. When you push at certain angle, you are exhibiting two forces as shown in diagram 1.
- Horizontal force acting along the plane.
- Vertical force downward perpendicular to the surface.
Case 2: <u>Pulling</u> Diagram 2
Pulling on a rope similar object at the same angle, the pull can be divided into two parts, one is horizontal that can help the box move, and one is vertically upwards, which decreases the downwards force of the box (a subtraction in the gravity) and thus decreases friction, making it very easy to pull. When you pull at a certain angle, you are exhibiting two forces as shown in diagram 2.
- Horizontal force acting along the plane.
- Vertical force upward perpendicular to the surface.
So, in the case of pushing, it adds an extra weight on the object, which results in difficulty to push that object at the same angle. In case of pulling, the upward perpendicular force, it tries to lift the object upward and divided the weight partially. Thus making it easier to move the object at same angle.
Answer:
Economics is the study of how societies use scarce resources to produce valuable commodities and distribute them among different people.
Explanation:
The ultimate goal of economic science is to improve the living conditions of people in their everyday lives.
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Answer:
The electric charge, q (in coulomb units) = 5004 C
Given:
The charge stored as printed on NiMH battery, q = 1390 mAh
Solution:
To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:
1 mA = 
1 hour = 
Also, we know that the rate of flow of charge is electric current, I:
I = 
⇒ q = [tex]I\times t[tex] (1)
where
q = electric charge
I = current
t = time taken for flow of current
Using eqn(1), we get:
q = [tex]1390\times 10^{-3}\times 60\times 60[tex]
q = 5004 A-s = 5004 C
Explanation:
Let thermal capacity of the vessel be C' J K-1
Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J
Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J
Heat energy taken by vessel = C' x (30 - 20) = 10 C' J
If there is no loss of heat energy,
Heat energy given by hot water = Heat energy taken by cold water and vessel
or 5040 = 2100 + 10 C'
or 10 C' = 2940
or C'= 294 J K-1
Thus, thermal capacity of vessel = 294 J K-1.
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Answer:
Explanation:
Now for this kind of phenomena in which drag cars are very elongated with front wheels placed far away from the rear wheels resulting in keeping the car front end from nosing upward,this is due to the reason because it helps in shifting the center of mass towards the front.
Hence when the car accelerates
torque due to gravity = torque due to air friction
