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Sonbull [250]
3 years ago
7

An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above

the launch point. Determine this maximum height.
A) 96m
B) 32m
C) 48 m
D) 75m
E) 64 m
Physics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

v0 = 25 m/s

vf = 0 m/s

a = -9.80 m/s^2

change in x = 31.89m

but that's only 1/3 of the hight, so i time it by 3 to get 96m

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Answer:

v_{ average} = 5.57

Explanation:

The most probable value of a measure is

       v_average = \frac{1}{N} ∑ x_i

where N is the number of measurements

in tes case N = 3

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Answer:

DETAILS IN THE QUESTION INSUFFICIENT TO ANSWER

Explanation:

Assuming the liquid to be water ,

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which is not possible

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