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nikdorinn [45]
3 years ago
7

Which statement accurately describes impulse?

Physics
2 answers:
KiRa [710]3 years ago
7 0

Answer:

Impulse is related to momentum because impulse is a term that describes object's change in momentum. The measurable quantity of momentum changing is called impulse.

netineya [11]3 years ago
4 0

Answer:

Impulse is equal to the change in momentum.

Explanation:

It was a risk,but I took it and it was the right answer

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Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacit
malfutka [58]

Answer:

T_2 = 77.5c

Explanation:

From the question we are told that

Temp of first boltsT_1=100

Temp of 2nd bolt T_2=55

Generally the equation showing the relationship between  heat & temperature is given by

  q=cm \triangle T

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     -(0.45*m* (T_2-100  \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)

     -(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)

      T_2 +T_2= 100 \textdegree c+55 \textdegree c

      T_2=\frac{155 \textdegree c}{2}

      T_2 = 77.5 \textdegree c

Therefore T_2 = 77.5 \textdegree c is the final temperature inside the container

5 0
3 years ago
True or false 6.02x10^23 atoms of oxygen have a mass of 16g ?
il63 [147K]

Answer:

True

Explanation:

The atomic mass of oxygen is 16amu, which means the <em>molar mass</em>, the mass of one mole of oxygen atoms (1 mole = 6.02x10²³), is 16g.

5 0
3 years ago
The value of acceleration due to gravity is less at the top of Mount Everest then that in the terai reason, why?​
xxTIMURxx [149]

Answer:

The value of acceleration due to gravity is greater in terai than in mountain. In terai region the radius of earth is less as it lies close to the centre of the earth. Thus, the value of g is more in terai region.

3 0
3 years ago
Why is ammeter connected in series in an electric circuit?
topjm [15]
In order to measure the size of the electrical current flowing in the circuit,
the current must pass through the meter.
8 0
4 years ago
The two masses in the Atwood's machine shown in the figure are initially at rest at the same height. After they are released, th
Inga [223]

According to the description given in the photo, the attached figure represents the problem graphically for the Atwood machine.

To solve this problem we must apply the concept related to the conservation of energy theorem.

PART A ) For energy conservation the initial kinetic and potential energy will be the same as the final kinetic and potential energy, so

E_i = E_f

0 = \frac{1}{2} (m_1+m_2)v_f^2-m_2gh+m_1gh

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

PART B) Replacing the values given as,

h= 1.7m\\m_1 = 3.5kg\\m_2 = 4.3kg \\g = 9.8m/s^2 \\

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

v_f = \sqrt{2(9.8)(1.7)(\frac{4.3-3.5}{3.5+4.3})}

v_f = 1.8486m/s

Therefore the speed of the masses would be 1.8486m/s

6 0
4 years ago
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