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3 years ago

6

Zain owes $1,312.50 for a new computer. An equal amount will be taken from his bank account each month for 10 1/2 months. How mu

ch will be taken out each month?

1 answer:

Basile [38]3 years ago

5 0

$1,312.50/10.5
$125

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If the length of the longest side of a right triangle is 10 inches is 60 degrees, what is the length (in inches) of the shortest

Scorpion4ik [409]

Yep 5 is correct! Good job

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3 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

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3 years ago

Write the equation of the line that passes through (2, 4) and has a slope of –1 in point-slope form.

klemol [59]

Point slope form is just a point and the slope written in the form y-y1 =m (x-x1).
Where x1 and y1 (should be subscripts) are (x1,y1) the point you are given.
So in this case all you must do is plug in the given values:

( y-y1 ) = m ( x-x1 )
( y-4. ) = -1 ( x-2 )
This being your answer

I hope this helps!!

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3 years ago

Read 2 more answers

A lake near the Arctic Circle is covered by a 222-meter-thick sheet of ice during the cold winter months. When spring arrives, t

Ivanshal [37]

S(t) = 3.82 - 0.2t

Step-by-step explanation:

After 7 weeks, the ice is 2.42 meters thick. The ice loses 0.2 meters of thickness per week; this means on the 7th week, it has lost 7(0.2) = 1.4 meters of thickness.

This means the ice started at 2.42+1.4 = 3.82 meters thick.

Our function will start at the original thickness of the ice, 3.82 meters.

Since the ice is losing thickness, we will subtract; it loses at a rate of 0.2 meters per week (t), which gives us 0.2t. This is subtracted from the original, 3.82 meters, giving us

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2 years ago

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The side of a square is 2.5 cm. Find its perimeter and area.

Neko [114]

Answer:

Perimeter = 10 cm

Area = 6.25 cm²

Step-by-step explanation:

$\bf \: Given :$

$\sf \: Side \: of \: the \: square = 2.5 \: cm$

$\bf \: To \: find:$

$\rightarrow \sf \: Perimeter$

$\sf\rightarrow Area$

$\bf \: Solution :$

$\rm \: First \: w e \: need \: to \: find \: out \: the \: perimeter \: o f \: it.$

So to find the Perimeter of the square, we'll use this formula :

$\boxed{ \sf\longrightarrow \: Perimeter = 4 \times side}$

$\bf \: Step \: 1 : \rm \: Put \: the \: value \: of \: side \: of \: the \: square :$

$\sf\longrightarrow \: Perimeter = (4 \times 2.5)cm$

$\bf \: Step\;2 : \rm Multiply :$

$\sf\longrightarrow \: Perimeter = 10 \: cm$

Hence, the perimeter would be 10 cm .

$\rule{225pt}{2pt}$

$\sf \: Now,\; let's\; find \: the \: Area .$

We know that the formula of Area to find the square is,

$\boxed{ \sf \longrightarrow \: Area = (side) {}^{2} }$

Note : The answer would always be in cm².

$\bf Step\; 1 :\rm Put\; the\; value \; of\; side \; of \; the\; square :$

$\sf\longrightarrow{Area} = (2.5) {}^{2} \: cm {}^{2}$

$\sf\longrightarrow{Area} = (2.5 × 2.5 ) \: cm {}^{2}$

$\bf \: Step\;2 : \rm Multiply :$

$\longrightarrow\sf \: Area = 6.25 \: cm {}^{2}$

Hence, the area of the square would be 6.25 cm².

<em>We are done !</em>

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

:D

3 0

2 years ago