A line that passes through the points (2,7) and (6,15)
Show work.
1 answer:
Answer:
The equation of the line is y = 2x + 3
Step-by-step explanation:
In order to find this, we first need to find the slope. For that we use slope intercept form.
m(slope) = (y2 - y1)/(x2 - x1)
m = (15 - 7)/(6 -2)
m = 8/4
m =2
Now that we have this, we can use the slope and either point in slope-intercept form to get the equation.
y - y1 = m(x - x1)
y - 7 = 2(x - 2)
y - 7 = 2x - 4
y = 2x + 3
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Step-by-step explanation:
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y=mx+b
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Step-by-step explanation:
Answer:
DHGB
======================
1. D
- -4x + 2y = 8 ⇒ -2x + y = 4 ⇒ y = 2x + 4
- Parallel line has same slope of 2
- y = 2x - 5
2. H
- Slope is: (2-4)/(3-(-3)) = -2/6 = -1/3
- Perpendicular line has negative reciprocal slope: -1/3 → 3
- y = 3x - 2
3. G
- Slope is: (2 - (-2))/(0 - (-1)) = 4/1 = 4
- Parallel line has same lope of 4
- y = 4x - 7
4. B
- 3x + y = 1 ⇒ y = -3x + 1
- Perpendicular line has negative reciprocal slope: -3 → 1/3
- y = 1/3x + 2
