Answer:
(8y+8)²+(4x²+16)=0
Step-by-step explanation:
Given:
(64y²)+(4x²)+128y+16x+64=0
Find:
Equation into the appropriate form
Computation:
(64y²)+(4x²)+128y+16x+64=0
(8y)²+(2x)²+128y+16x+64=0
(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0
(8y+8)²+(4x²+16)=0
Let's start with a picture.
We see RST is smaller, and BC is parallel to but in the opposite direction to its corresponding segment ST. Both have slope -1.
If we look at the difference of points (technically called vectors but we don't have to go there) we get
C-B=(-2,2)
T-S=(1,-1)
Without further calculation we can see T-S is half the length of C-B.
The problem asks for a dilation followed by a reflection. We know the dilation scale is k=1/2 because the new triangle is half the size.
After dilation we get A'B'C':
A'(3,2), B'(-1,0), C'(-2,1)
We see now we need a reflection that flips the coordinates x and y. That's the +45° line through the origin, namely y=x.
Answer: k=1/2, y=x
Yes. Because blah blah blas blah blah blah
XD
X + 7x = 56 + 8
Simplifying x + 7x = 56 + 8 Combine like terms: x + 7x = 8x 8x = 56 + 8 Combine like terms: 56 + 8 = 64 8x = 64 Solving 8x = 64 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Divide each side by '8'. x = 8 Simplifying x = 8
Plug in -3 in the x.
4(2)(-3)= -24.
