1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivann1987 [24]
3 years ago
10

Which quantity is directly related to the temperature of a substance?

Physics
2 answers:
dolphi86 [110]3 years ago
5 0
A: average kinetic energy of the particles in the substance
vovikov84 [41]3 years ago
4 0
The answer is A. The kinetic energy
You might be interested in
What is the angle of reflection?
hoa [83]
I can guarantee you that it is not
C.<span>the angle that the incident ray makes with a line drawn perpendicular to the reflecting surface  I hope this somewhat helps</span>
4 0
3 years ago
A 5kg rock and a 10kg rock are dropped from a height of 10m?
fredd [130]
Look out below ! You should step nimbly to one side, to avoid being hit by one or the other of those hazardous weight objects when they arrive (at the same time).
5 0
2 years ago
What is planned goal for the Europa clipper mission
noname [10]
It's being planned to launch in the 2020's
5 0
3 years ago
Something that can not be used up or depleted​
Jet001 [13]

Answer:

oxygen

Explanation:

as it is in the air it can't be depleted or used up

5 0
3 years ago
Read 2 more answers
At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi
Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36.  Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and \mu be the friction coefficient and m be the mass of car.

Hence, the given data is as follows.

                v = 0,     s = 84 m,     \mu = 0.36

According to Newton's law of second motion the expression for acceleration is as follows.

                      F = ma

                 -\mu N = ma

                 -\mu mg = ma

                      a = -\mu g

Also,    

               v^{2} = u^{2} + 2as

              (0)^{2} = u^{2} + 2(-\mu g)s

                  u^{2} = 2(\mu g)s

                            = \sqrt{2(0.36)(9.81 m/s^{2})(84 m)}

                            = 24.36 m/s

Thus, we can conclude that the speed of the car when the driver slammed on (and locked) the brakes is 24.36 m/s.

4 0
3 years ago
Other questions:
  • What happens to the saturation for when adding salt to water at room temperature
    11·1 answer
  • List of priceless your bodies from largest to smallest in terms of their distance from earth
    12·1 answer
  • How do I calculate the speed of light and the distance between the earth and the moon?
    11·1 answer
  • The boiling point of water at sea level is 100 °c. at higher altitudes, the boiling point of water will be
    8·1 answer
  • A playground merry-go-round of radius 2.00 m has a moment of inertia I = 275 kg · m2 and is rotating about a frictionless vertic
    15·1 answer
  • Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
    14·2 answers
  • Which factor can increase both potential energy and kinetic energy of an object?
    6·1 answer
  • 9- Under what circumstances would a vector have components that are equal in
    13·1 answer
  • The speed limit sign in indiana reads 60 miles per hour. convert these units to meters per second
    15·1 answer
  • How did the angular acceleration change with the new moment of inertia? was your prediction correct?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!