The change in velocity is +4 m/s to the right (or -4 m/s to the left).
The object's mass is irrelevant.
Answer:
6.57 m/s
Explanation:
First use Hook's Law to determine the F the compressed spring acts on the mass. Hook's Law F=kx; F=force, k=stiffnes of spring (or spring constant), x=displacement
F=kx; F=180(.3) = 54 N
Next from Newton's second law find the acceleration of the mass.
Newton's .2nd law F=ma; a=F/m ; a=54/.75 = 72m/s²
Now use the kinematic equation for velocity (or speed)
v₂²= v₀² + 2a(x₂-x₀); v₂=final velocity; v₀=initial velocity; a=acceleration; x₂=final displacement; x₀=initial displacment.
v₀=0, since the mass is at rest before we release it
a=72 m/s² (from above)
x₀=0 as the start position already compressed
x₂=0.3m (this puts the spring back to it's natural length)
v₂²= 0 + 2(72)(0.3) = 43.2 m²/s²
v₂=
= 6.57 m/s
Answer:
a) 
b) 
Explanation:
Given:
String vibrates transversely fourth dynamic, thus n = 4
mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg
Tension in the string, T = 8.39 N
Length of the string, L = 1.87 m
a) we know

where,
= wavelength
on substituting the values, we get

or

b) Speed of the wave (v) in the string is given as:

also,

equating both the formula for 'v' we get,

on substituting the values, we get

or

or

The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.
<h3>What is magnetic force?</h3>
A magnetic force is the force that act in a magnetic field.
To calculate the magnetic force, we use the formula below.
Formula:
- F = qvB.........Equation 1
Where:
- F = magnetic force
- q = point charge
- v = Velocity of the the charge
- B = Field strength
From the question,
Given:
- q = 5.0×10⁻⁷ C
- v = 2.6×10⁵ m/s
- B = 1.8×10⁻² T
Substitute these values into equation 2
- F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
- F = 23.4×10⁻⁴
- F = 2.34×10⁻³ N
Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.
Learn more about magnetic force here: brainly.com/question/2279150
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The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.
<u>Explanation:</u>
As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.
The final kinetic energy is
= 7500 J
As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.
Work done = Final Kinetic energy - Initial Kinetic energy
Thus the work utilized for moving the car is
Work done = 7500 J - 0 J = 7500 J
Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.