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Gala2k [10]
3 years ago
12

Drew wants to convert square mils to circular mils in an area calculation. How does he do this?

Physics
1 answer:
bija089 [108]3 years ago
6 0

Answer:

i dont know

Explanation:

blah blah blah your welcome

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The ability of atoms to attract electrons is referred to as
dexar [7]

Answer: electronegativity

Explanation:

Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.  

The size of an atom decreases as we move across the period because the electrons get added to the same shell and the nuclear charge keeps on increasing. Thus the electrons get more tightly held by the nucleus.

As, the size of an element decreases, the valence electrons come near to the nucleus. So, the attraction between the nucleus and the shared pair of electrons increases and thus the electronegativity increases.

8 0
4 years ago
Read 2 more answers
A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally
Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, g=-9.8 m/s^2, downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

v_x = +2.60 m/s

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

v_y = u_y +gt

where

u_y = 0 is the initial vertical velocity, which is zero

g=-9.8 m/s^2 is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

v_y = 0+(-9.8)(1.75)=-17.2 m/s

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0
3 years ago
How fast must a 2500-kg elephant move to have the same kinetic energy as a 67.0-kg sprinter running at 15.0 m/s
abruzzese [7]

Answer:

2.45 m/s

Explanation:

kinetic energy = 1/2 * m * v^2

then, 0.5 * 2500 * x^2 = 0.5 * 67 * 15^2

by solving for x, X = 2.45 m/s

6 0
3 years ago
Which component of the microscope is found directly under the stage, and contains two sets of lenses that collect and concentrat
dusya [7]

Answer: CONDENSER

Explanation:

CONDENSER is the component of the microscope that is found directly under the stage, and contains two sets of lenses that collect and concentrate light as it passes upward from the light source into the lens systems. The condenser increases the resolution of light.

A microscope is an instrument that is used in laboratory to examine objects that can't be viewed with the naked eye. This is possible with as it is designed with lenses that aids in magnification of the objects.

7 0
4 years ago
A sanding disk with rotational inertia 3.8 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit
Elis [28]

Answer:

(a) Angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b) Angular velocity of the disk is 353\frac{rad}{s}

Explanation:

Given

Rotational inertia of the disk , I=3.8\times 10^{-3}kg.m^{2}

Torque delivered by the motor , \tau =17N.m

Torque is applied for duration , \Delta t=79ms=0.079s

(a)

Magnitude of angular momentum of the disk = Angular impulse produced by the torque

\therefore L=\tau \Delta t=17\times 0.079\frac{kg.m^{2}}{s}

=>L=1.343\, \frac{kg.m^{2}}{s}

Thus angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b)

Since Angular momentum , L=I\omega

where \omega= Angular velocity of the disk

=>\omega =\frac{L}{I}=\frac{1.343}{3.8\times 10^{-3}}\frac{rad}{s}

\therefore \omega =353\frac{rad}{s}

Thus angular velocity of the disk is 353\frac{rad}{s}

5 0
3 years ago
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