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3 years ago

Assignment S of write the Symbol Told, mercury and Cooper, Iron, Lead

Physics

1 answer:

m_a_m_a [10]3 years ago

3 0

Answer:

Check explanation

Explanation:

Gold - Au (Aurum)

Mercury - Hg (Hydrargyrum)

Copper - Cu (Cuprum)

Iron - Fe (Ferrum)

Lead - Pb (Plumbum)

These elements in the periodic table are some of the elements represented by letters not in line with their names.

This is because, these elements were known in ancient times and therefore, they are represented by letters from their ancient names.

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3 years ago

You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo

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Answer:

λ = 5.734 x 10⁻⁷ m = 573.4 nm

Explanation:

The formula of the Young's Double Slit experiment is given as follows:

$\Delta x = \frac{\lambda L}{d}\\\\\lambda = \frac{\Delta x d}{L}$

where,

λ = wavelength = ?

L = distance between screen and slits = 8.61 m

d = slit spacing = 1.09 mm = 0.00109 m

Δx = distance between consecutive bright fringes = $\frac{4.53\ cm}{10}$ = 0.00453 m

Therefore,

$\lambda = \frac{(0.00453\ m)(0.00109\ m)}{8.61\ m}$

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3 years ago

A yo‑yo with a mass of 0.0800 kg and a rolling radius of =2.70 cm rolls down a string with a linear acceleration of 5.70 m/s2.

N76 [4]

Explanation:

Given that,

Mass, m = 0.08 kg

Radius of the path, r = 2.7 cm = 0.027 m

The linear acceleration of a yo-yo, a = 5.7 m/s²

We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.

(a) Tension :

The net force acting on the string is :

ma=mg-T

T=m(g-a)

Putting all the values,

T = 0.08(9.8-5.7)

= 0.328 N

(b) Angular acceleration,

The relation between the angular and linear acceleration is given by :

$\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{5.7}{0.027}\\\\=211.12\ m/s^2$

(c) Moment of inertia :

The net torque acting on it is, $\tau=I\alpha$ , I is the moment of inertia

Also, $\tau=Fr$

So,

$I\alpha =Fr\\\\I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{0.328\times 0.027}{211.12}\\\\=4.19\times 10^{-5}\ kg-m^2$

Hence, this is the required solution.

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3 years ago

How many 90-W, 120-V light bulbs can be connected to a 20-A, 120-V circuit without tripping the circuit breaker? (Note: This des

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Answer:

Explanation:

Total power of the circuit

P = V × I = 120 × 20 = 2400 W

Power of each bulb = 90 W

Number of bulbs which work without tripping

N = power of circuit / power of each bulb

N = 2400 / 90

N = 26.66

Number of bulbs should be integer so the number of bulbs be 26.

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3 years ago

calculate the initial velocity of an object displaced 33 meters while accelerating 8 m/s^2 to a final velocity of 68 m/s how do

Grace [21]

Use the equation

${v_f}^2-{v_i}^2=2a\Delta x$

The final velocity $v_f$ is 68 m/s, the acceleration $a$ is 8 m/s^2, and the net displacement $\Delta x$ is 33 m, so you can solve for the initial velocity $v_i$ :

$\left(68\,\dfrac{\mathrm m}{\mathrm s}\right)^2-{v_i}^2=2\left(8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(33\,\mathrm m)$

${v_i}^2=4096\,\dfrac{\mathrm m^2}{\mathrm s^2}$

$v_i=64\,\dfrac{\mathrm m}{\mathrm s}$

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3 years ago