Answer:
88° and 132°
Step-by-step explanation:
The sum of angles in a pentagon ( a 5-sided shape) is given as
= (5 - 2) 180°
= 540°
The angles ∠EAB and ∠AED are supplementary hence the sum is 180° Therefore,
∠AED + 110 = 180
∠AED = 180 - 110
= 70°
Given that the sum of the angles in a pentagon is 540° then
110 + 70 + 2k + 140 + 3k = 540
5k + 320 = 540
5k = 540 - 320
5k = 220
k = 220/5
= 44°
Hence the angle ∠ABC
= 2 × 44
= 88°
∠CDE
= 3 × 44
= 132°
You want to figure out what the variables equal to, all of these are parallelograms meaning opposite sides and angles are equal to each other.
In question 1 start with 3x+10=43, this means that 3x is 10 less than 43 which is 33, 33 divided by 3 is 11 meaning x=11.
Same thing can be done with the sides 124=4(4y-1), start by getting rid of the parentheses with multiplication to get 124=16y-4, this means that 16y is 4 more than 124, so how many times does 16 go into 128? 8 times, so x=11 and y=8
Question 2 can be solved because opposite angles are the same in a parallelogram, so u=66 degrees
You can find the sum of the interial angles with the formula 180(n-2) where n is the number of sides the shape has, a 4 sided shape has a sum of 360 degrees, so if we already have 2 angles that add up to a total of 132 degrees and there are only 2 angles left and both of those 2 angles have to be the same value then it’s as simple as dividing the remainder in half, 360-132=228 so the other 2 angles would each be 114, 114 divided into 3 parts is 38 so u=66 and v=38
Question 3 and 4 can be solved using the same rules used in question 1 and 2, just set the opposite sides equal to each other
Answer:
x = 12
Step-by-step explanation:
1 + 11 = 12, so x = 12. hope this helps
Answer:
B and C
Step-by-step explanation:
Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
<h3>
(See picture attached for sub-totals)
</h3>
a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%
