Question

what is the new pressure acting on a 2.5 l balloon if its original volume was 5.8 l at 3.7 ATM of pressure

Answer 1

Answer : The new pressure acting on a 2.5 L balloon is, 8.6 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure = 3.7 atm

$P_2$ = final pressure = ?

$V_1$ = initial volume = 5.8 L

$V_2$ = final volume = 2.5 L

Now put all the given values in the above equation, we get:

$3.7atm\times 5.8L=P_2\times 2.5L$

$P_2=8.6atm$

Thus, the new pressure acting on a 2.5 L balloon is, 8.6 atm.