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3 years ago

11

How does atomic hydrogen torch function for cutting and welding purposes

1 answer:

lbvjy [14]3 years ago

5 0

Explanation:

atomic hydrogen torch utilizes an electric arc whereby two closely - but not touching electrodes - result in the release of powerful electric spark as the current tries to flow through the gap. The gap is filled with hydrogen gas in an atomic hydrogen torch rather than air. The electric arch is split the hydrogen gas molecules into hydrogen atoms (some in plasma form). When the hydrogen atoms land on cooler objects like the metal being welded or cut, they region back to H₂ molecules releasing enormous amounts of heat on the surface. Surface temperatures can reach 4000 °C. The use of hydrogen gas protects the metal being welded from oxidation. Oxidation may compromise the quality of the weld.

Learn More:

For more on other welding torches check out;

brainly.com/question/13335545

brainly.com/question/13056701

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nguyên tử sắt có điện tích hạt nhân là 26+. trong nguyên tử, số hạt mang điện nhiều hơn số hạt không mang điện là 22. Hãy xác đị

dimaraw [331]

Answer:

I don't know yr language

8 0

3 years ago

Daniel claims that the product of two square roots of integers is always rational. His reasoning is given in the example below.

Katen [24]

Incorrect....................

6 0

3 years ago

Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen

alexgriva [62]

Answer:

$V_{base}=24.04mL$

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

$2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O$

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

$2M_{base}V_{base}=M_{acid}V_{acid}$

Therefore, for is to compute the volume of the used base, we proceed as shown below:

$V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}$

And we plug in to obtain:

$V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL$

Best regards!

8 0

3 years ago

When balance the following chemical equations N2+O2= NO2 the coefficient for O2 is

Papessa [141]

Answer:

2

Explanation:

N₂ + O₂ ---> NO₂

balance

N₂ + 2O₂ ---> 2NO₂

4 0

2 years ago

weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the

valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 751 mm Hg

$P_2$ = final pressure of gas = 495 mm Hg

$V_1$ = initial volume of gas = 340 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $30^oC=273+30=303K$

$T_2$ = final temperature of gas = $-27^oC=273-27=246K$

Now put all the given values in the above equation, we get:

$\frac{751\times 340}{303}=\frac{495\times V_2}{246}$

$V_2=419L$

Thus the volume of the balloon at this altitude is 419 L

8 0

3 years ago