Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
1.6 × 10²³ molecules of N2O5
Explanation:
To find the amount of molecules from the amount of moles of a substance we simply multiply the amount of moles by Avagadro's number.
0.27mol × 6.02×10²³ = 1.6 × 10²³ molecules of N2O5
Answer:
Explanation:
Hello,
In this case, the molecular chemical reaction is:
Thus, by considering the ionic species we have:
Wherein the ammonium and bromide ions are spectator ions since nickel (II) phosphate is largely insoluble in water, therefore, the net ionic equation is:
Best regards.
