I’m not really sure but I wanna think I te catiónic
Answer:
1- Yes, we can calculate the solubility of mineral compound X.
2- 0.012 g/mL.
Explanation:
<em>1- Using only the information above, can you calculate the solubility of X in water at 15.0 °C? </em>
The information available is:
The volume of water sample = 25.0 mL.
Weight of the mineral compound X after evaporation, drying, and washing = 0.30 g.
∴ Yes, we can calculate the solubility of mineral compound X.
<u><em>2- If you said yes, calculate it.</em></u>
∵ 25.0 mL of water sample contains → 0.30 g of the mineral compound X.
∴ 1.0 mL of water sample contains → ??? g of the mineral compound X.
1.0 ml of water sample will contain (0.3 g/25.0 mL) 0.012 g.
<em>∴ The solubility of the mineral compound X in the water sample is</em> <u><em>0.012 g/mL.</em></u>
<u><em></em></u>
Answer:
5 L
Explanation:
So this problem refers to Charles's law. You would use this formula..
(Initial volume / Initial Temperature) = (Final volume / Final Temperature)
For your problem, it would look like this...
You would cross multiply and your answer would be 5L.
To reassure yourself that the answer is correct, Charles law states that the Volume and the Temperature are directly proportional. Meaning if your temperature is decreasing, your volume <u>has</u> to decrease.
Answer:
4Hg+2O2=4HgO
four Mercury + four oxygen
