Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.
because some system are so large,small,or complex they are difficult to predict
Answer:
Since valence shells are mostly empty in nonmetal atoms, the atoms attract and hold any electrons they can in order to fill their valence shells.
If my memory serves me well, the right one is B. There is equal number of each type of atom on the reactant and product side. Check it, if I'm wrong.
