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yulyashka [42]
3 years ago
15

Balance the following equation by adding the correct mole numbers.P⁴+Cl²->PCl³​

Chemistry
1 answer:
marta [7]3 years ago
6 0

Hey there!

P₄ + Cl₂ → PCl₃

First, let's balance Cl.

There are 2 on the left, and 3 on the right.

To balance this, let's put a coefficient of 3 in front of Cl₂ and a coefficient of 2 in front of PCl₃.

P₄ + 3Cl₂ → 2PCl₃

Now we have 6 on the left and 6 on the right.

Next, let's balance P.

There are 4 on the left and 2 on the right.

Let's change the coefficient in front of PCl₃ from 2 to 4.

P₄ + 3Cl₂ → 4PCl₃

There are now 4 P on each side.

However, now Cl is unbalanced, with 6 on the left and 12 on the right.

We can change the coefficient in front of Cl₂ from 3 to 6.

P₄ + 6Cl₂ → 4PCl₃

So now, we have 4 P on each side and 12 C on each side.

This is our final balanced equation.

Hope this helps!

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The chemical properties of organic molecules are determined by specific arrangements of atoms called _____________.
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Answer:

Functional group

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7 0
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Noble gases are the least reactive elements on the periodic table.<br> A. True<br> B. False
Nezavi [6.7K]
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7 0
3 years ago
Read 2 more answers
If the pressure on a gas at -73°C is doubled but its volume is held constant, what will its final temperature be in degrees Cels
Gre4nikov [31]

Answer:

127°C

Explanation:

This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.

We convert our value to K → -73°C + 273 = 200 K

The moles are the same, and the volume is also the same:

P₁ / T₁ = P₂ / T₂

But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂

P₁ / 200K = 2P₁ / T₂

1 /2OOK = (2P₁ / T₂) / P₁

See how's P₁ term is cancelled.

200K⁻¹ = 2/ T₂

T₂ = 2 / 200K⁻¹  → 400K

We convert the T° to C → 400 K - 273 = 127°C

4 0
2 years ago
How many significant digits are in the number 125,001?
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The number of significant digits in the number 125,001 are: <span>6. 

</span>Significant digits are always:
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</span>3. <span>A final zero or trailing zeros in the decimal portion only are significant.

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3 years ago
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