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Maslowich
3 years ago
10

What does inertia depend on??

Chemistry
2 answers:
zubka84 [21]3 years ago
3 0
Inertia depends on the mass of an object. 
Rainbow [258]3 years ago
3 0

It depends on a mass of an object.
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Calculate the density mass= 54.2 volume= 78.1
Helen [10]

Answer:

0.693 (you can round it up if you want to)

Explanation:

Density= mass ÷ volume

54.2 ÷ 78.1 = 0.693

I hope this helped☺

6 0
3 years ago
would you like to explore outer space? Why or why not? If you could travel to any part of the galaxy at lightning speed would li
morpeh [17]

Answer:

Yes!

Explanation:

I think It would be fun!, Going thought space going from planet to planet. once i get back to earth i can make a document about my time in space.

4 0
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An element has 3 electrons, 3 protons and 4 neutrons. What will be its atomic number and mass number? (​
stiv31 [10]

Answer:

its atomic number will be 3 and it's mass number will be 7. it is lithium

8 0
2 years ago
Name each subatomic particle, its charge, and its location in an atom.
Tpy6a [65]
Protons: charge +1, have a mass of 1 and are found in the nucleus 

Neutrons: charge 0, have a mass of 1 and are found in the nucleus

Electrons: charge -1, have a mass of 1/840 and are found on the outside of the nucleus 

hope that helps 
4 0
3 years ago
Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
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