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pickupchik [31]
3 years ago
9

Example of chemical reaction.

Chemistry
1 answer:
defon3 years ago
4 0

Answer:

Photosynthesis

Plants apply a chemical reaction called photosynthesis to convert carbon dioxide and water into food (glucose) and oxygen.

Anaerobic respiration

Anaerobic respiration is a set of chemical reactions that allows cells to gain energy from complex molecules without oxygen.

Combustion

You strike a match, burn a candle, build a fire, or light a grill, you see the combustion reaction.

Electrochemistry

Batteries use electrochemical or redox reactions to convert chemical energy into electrical energy.

Explanation:

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Why doesn't gold react with oxygon
lara31 [8.8K]
Give me a thanks I been helped a lot of people and non of them is thanks me.

<span>Gold have a single outer electron. This seems disadvantageous, energy-wise, until you look at the orbitals the electrons are in. The lone electron is in an S-orbital. This orbital is thus half full (since s-orbitals can contain 2 electrons), whereas all the other inner orbitals in silver and gold are filled, and hence exceptionally stable. After a full orbital, the next most stable orbital is a half full one. </span>
6 0
3 years ago
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
3 years ago
Describe the relationship between temperature and particle movement
soldi70 [24.7K]

Answer:

If matter is heated and thus its temperature rises more and more, it can be seen that the particles contained in it move ever faster – be it the relatively free movement of the particles in gases or the oscillation around a rest position in solids. The temperature of a substance can therefore be regarded as a measure of the velocity of the particles it contains. With a higher temperature and thus higher particle

Explanation:

7 0
3 years ago
What mass of salt is needed to prepare 600 mL of a 4g/L solution?
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THE ALTERNATIVE IS 4.8g alternative c
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Examine the diagram shown. Which are the correct labels for continental plates 1 and 2?
Over [174]

Answer:

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Explanation:

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