V = 550 mL = 0.550 L
V = 22.4 L/mol (STP)
M(CO₂)=44.01 g/mol
n(CO₂)=v/V
m(CO₂)=n(CO₂)M(CO₂)=vM(CO₂)/V
m(CO₂)=0.550*44.01/22.4=1.08 g
Acid is an substance that ionized in water to produce hydrogen ion
Atom is the smallest neutral particle in the element
The full question can be seen below:
The decomposition of 
is represented by the equation above.
A student monitored the decomposition of a 1.0 L sample of 
at a constant temperature of 300K and recorded the concentration of 
as function of time. The results are given in the table below:
Time (s)
0 2.7
200 2.1
400 1.7
600 1.4
The 
produced from the decomposition of the 1.0 L sample of is collected in a previously evacuated 10.0 L flask at 300 K. What is the approximate pressure in the flask after 400 s?
(For estimation purpose, assume that 1.0 mole of gas in 1.0 L exerts a pressure of 24 atm at 300 K).
Answer:
1.2 atm
Explanation:
Considering all assumptions as stated above;
Initial 2.7 mole --- ---
Change -1.0 --- 
Equilibrium 1.7 mole --- 0.5 mole
To determine the concentration of O₂; we need to convert the moles to concentration for O₂ = 
= 
= 0.05 
Thus, based on the assumption that "1.0 mole of gas in 1.0 L exerts a pressure of 24 atm"
∴ 0.05 will give rise to = 0.05 × 24
= 1.2 atm
The dilution factor of the unknown sample is 10. The dilution factor of a solution refers to the ratio of the final volume of the now diluted solution to the initial volume of the of the initial concentrated solution.
Mathematically;
The dilution factor is given by the formula;
Dilution factor = Final volume of the now diluted solution/ Initial volume of more concentrated solution
Final volume of the now diluted solution = 100.0 ml
Initial volume of more concentrated solution = 10.00 ml
Dilution factor = 100.0 ml/10.00 ml
Dilution factor = 10
Learn more: brainly.com/question/20113402
I believe that the molar mass is 342.34g/mol
