Answer:
19.5 in²
Step-by-step explanation:
A applicable formula for the area of the smaller triangle is ...
A = (1/2)ab·sin(C) . . . . where a, b are the given sides and C is the angle between them.
The side lengths are 3 in and 13 in, so the area is ...
A = (1/2)(3 in)(13 in)sin(C) = (19.5 in²)sin(C)
The sine function is a maximum at C=90°, at which angle it has the value 1. So, the maximum area is that of a right triangle of sides lengths 3 and 13 inches.
The maximum area is 19.5 in².
midsegment is the segment connecting the midpoints of two sides of a triangle
Answer:
FILAC
Step-by-step explanation:
SY UN CRCK TINE QNEUEER S 2O00 X QES N URAONT 2
0
-3 (-4 + -x ) = (-4(x) × 2 ) + 6
-3 (-4-x) = (-4x × 2) + 6
-12 + 3x = -8x + 6
3x - 12 = 6 - 8x
add 8x on both sides
11x - 12 = 6
add 12 on both sides
11x = 18
<em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>1</u></em><em><u>/</u></em><em><u>1</u></em><em><u>8</u></em>
-8 = trevon
(3/4)-8 = beth
= -6
1/4[(3/4)-8] = leah
1/4(-6)
= -1.5
