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Charra [1.4K]
3 years ago
9

What’s 1 2/6 + 3 4/8. Help

Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

4 \frac{5}{6}

Step-by-step explanation:

We can write 1 \frac{2}{6} as \frac{8}{6} and we can write 3 \frac{4}{8} as \frac{28}{8}. So the question becomes \frac{8}{6} + \frac{28}{8}. We can simplify both fractions so that the expression is \frac{4}{3} + \frac{7}{2} and to add the two fractions we need to find a common denominator. The least common multiple of 2 and 3 is 6, so we want the denominator to be 6 in both fractions. To do this, we multiply \frac{4}{3} by \frac{2}{2} and we multiply \frac{7}{2} by \frac{3}{3}.

So finally we get \frac{4}{3} \times \frac{2}{2} + \frac{7}{2} \times \frac{3}{3}, which is \frac{8}{6} + \frac{21}{6}, which is \frac{29}{6}.

And now all we have to do is rewrite the improper fraction \frac{29}{6}. Notice 6 goes into 29 exactly 4 times, with a remainder of 5. So the expression simplifies to 4 \frac{5}{6}

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luda_lava [24]
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
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Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>

Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
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<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>

Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2

<span>sqrt(y+9) = (2x + 2) / 2sqrt(2) 
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>

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