Data:
m (<span>Sample Mass) = ?
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (

)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
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Molar Mass

= 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

Solving:



Answer:
By approximation would be letter
D) <span>
337.2 g</span>
Answer:
A. Water particles barely move forward; they move in a circular pattern.
The answer is 28.02.
The chemical formula for cadmium nitrate is Cd(NO₃)₂.
There are in total 2 nitrogen atoms in Cd(NO₃)₂. If <span>the atomic weight of nitrogen is 14.01</span>, the mass <span>of two nitrogen atoms in one mole of cadmium nitrate is 28.02:
2 </span>· 14.01 = 28.02
8.................................