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skelet666 [1.2K]
3 years ago
15

Write the net ionic equation for the reaction of sodium phosphate with iron (III) chloride. Include the complete ionic equation

and label the spectator ions. Also be sure to label the reactants as products as solid, liquid, gas, or aqueous solutions
Chemistry
2 answers:
Xelga [282]3 years ago
8 0

Hi There!

Question - Write the net ionic equation for the reaction of sodium phosphate with iron (III) chloride. Include the complete ionic equation and label the spectator ions. Also be sure to label the reactants as products as solid, liquid, gas, or aqueous solutions

Answer: Fe3(+) + PO43(-) = FePO4

P.S. The + and - are in parentheses because they are below the number.

Hope This Helps :)

topjm [15]3 years ago
6 0

Write the net ionic equation for the reaction of sodium phosphate with iron (III) chloride. Include the complete ionic equation and label the spectator ions. Also be sure to label the reactants as products as solid, liquid, gas, or aqueous solutions

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Tray yucouum<br>82 (3x - 2)2 dx<br>a.<br>140<br>b. 120<br>C.<br>104<br>d. 100​
alekssr [168]

Answer:

cause it has more

space between molecules.

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Explanation:

8 0
3 years ago
A pair of students found the temperature of 100. g of water to be 26.5°C. They then dissolved 8.89 g of AgNO3 in the water. When
bekas [8.4K]

Explanation:

Initial temperature of the water = T_i=26.5^oC

Final temperature of the water = T_f=23.7^oC

a) Change in temperature of the water,ΔT = T_f-T_i

\Delta T=23.7^oC-26.5^oC=-2.8^oC

Change in temperature of the water,ΔT is -2.8°°C.

b) Endothermic reaction : Reaction in which heat absorbed and the temperature if the surrounding is decreased.

Exothermic reaction : Reaction in which heat released and the temperature if the surrounding is increased.

On dissolving silver nitrate in water the temperature of the water decreased 2.8 degree Celsius  which means that energy water was absorbed by solid silver nitrate to get dissolve in water. Hence, endothermic reaction.

(f)  Mass of silver nitrate = 8.89 g

Moles of silver nitrate = \frac{8.89 g}{170 g/mol}=0.05229 mol

AgNO_3(aq)\rightarrow Ag^+(aq)+NO_3^-(aq)

1 mole of silver nitrate gives 1 mole of silver ion i.e. cation.

Then 0.05229 moles of silver nitrate will give:

\frac{1}{1}\times 0.05229 mol=0.05229 mol silver ions.

0.05229  moles of cations are produced.

1 mole of silver nitrate gives 1 mole of nitrate ion i.e. anion .

Then 0.05229 moles of silver nitrate will give:

\frac{1}{1}\times 0.05229 mol=0.05229 mol nitrate ions.

0.05229  moles of anion are produced.

5 0
3 years ago
A solution of H2SO4(aq) with a molal concentration of 5.25 m has a density of 1.266 g/mL. What is the molar concentration of thi
Igoryamba
<span>There are a number of ways to express concentration of a solution. This includes molarity and molality. Molarity is expressed as the number of moles of solute per volume of the solution.  MOlality is expressed as moles per kg solution. 

5.25 mol H2SO4 / kg solution ( 1 kg / 1000 g ) ( 1.266 g / mL ) ( 1000 mL / 1L ) = 6.6 M H2SO4</span>
5 0
3 years ago
1. Complete the balanced dissociation equation for the compound below. If the compound does not dissociate, write NR after the r
puteri [66]

Answer:

1. (NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

2. Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

Explanation:

The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

(NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

However very little S²- ions are present in solution due to the very basic nature of the S²- ion (Kb = 1 x 105).

The ammonium ion being a better proton donor than water, donates a proton to sulphide ion to form hydrosulphide ion which exists in equilibrium with aqueous ammonia.

S²- (aq) + NH₄+ (aq) ⇌ SH- (aq) + NH₃ (aq)

Aqueous solutions of ammonium sulfide are smelly due to the release of hydrogen sulfide and ammonia, hence, their use in making stink bombs.

2. The reaction between aluminium nitrate and sodium phosphatein aqueous solution is a double decomposition reaction whish results in the precipitation of insoluble aluminium phosphate. The equation of the reaction is given below :

Al(NO₃)₃ (aq) + Na₃PO₄ (aq) ----> AlPO₄ (s) + 3 NaNO₃ (aq)

The net ionic equation is given below:

Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

7 0
3 years ago
The process of pouring a mixture through a filter to catch the larger particles, while allowing the smaller particles to pass th
ki77a [65]
It’s is b. Filtration
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