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Brilliant_brown [7]
3 years ago
9

Please help! Due today!

Chemistry
1 answer:
insens350 [35]3 years ago
7 0

Answer:

five(5) of them

sorry if I'm wrong

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0.0145 moles of helium gas are introduced into a balloon so that the volume of the balloon is 2.54 liters. An additional amount
olga_2 [115]

Answer:

4.43L is final volume of the ballon

Explanation:

Avogadro's law of ideal gases states that <em>equal volumes of gases, at the same temperature and pressure, have the same number of molecules</em>.

The formula is:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

Where V and n are volume and moles of the gas in initial and final conditions.

If the initial conditions are 0.0145 moles and 2.54L and final amount of moles is 0.0253moles, final volume is:

\frac{2.54L}{0.0145mol} =\frac{V_2}{0.0253mol}

V₂ = <em>4.43L is final volume of the ballon</em>

6 0
3 years ago
What has modern media shown you about atoms
mash [69]
Atoms like in chemistry class?
8 0
3 years ago
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En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

5 0
3 years ago
Consider four elements from Group 17: fluorine in the second period, chlorine in the third period, bromine in the fourth period,
nika2105 [10]

Answer:

A. Fluorine

Explanation:

I got it right on Plato.

6 0
3 years ago
Which of the following is not a primary function of the products of the pentose phosphate pathway? a. To maintain levels of NADP
zlopas [31]

Answer: The correct answer is D.

Explanation:

As you can see in every step of the pathway, ATP is not generated directly. Although, in the oxidative phase, molecules of NADPH are produced and these can be used for synthesize ATP indirectly; the NADPH molecules are hihgly demanded in tissues that carry out constantly synthesis of fatty acids, such as liver.

Therefore the correct answer is D.

6 0
3 years ago
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