All categories

3 years ago

2. If 1.75 L of a gas is at 700. K and is under 250. kPa of pressure, what will the new

Chemistry

1 answer:

Andrews [41]3 years ago

3 0

Answer:

Final volume is 3.50L

Explanation:

It is possible to find volume of a gas using combined gas law:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state

If initial state of the gas is:

1.75L of a gas is at 700K and is under 250kPa of pressure

And final state is:

298K and 53.2kPa.

Replacing:

$\frac{250kPa*1.75L}{700K} =\frac{53.2kPa*V_2}{298K}$

0.625L = 0.1785*V₂

3.50L = V₂

Thus, final volume is 3.50L

You might be interested in

If the equilibrium concentration of NO, is 1.78 x 10-2 M, the equilibrium concentration of N2O4 is

padilas [110]

Answer:

The equilibrium lies to the left.

5.42 x 10^-2

Explanation:

3 0

4 years ago

A sample of sugar (C12H22O11) contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?

saveliy_v [14]

Answer: Option (a) is correct.

Explanation:

Molecules of sugar given = $1.505 \times 10^{23}$

According to Avogadro's number it is known that 1 mole contains $6.023 \times 10^{23}$ .

Therefore, calculate the moles of sugar present in the sample as follows.

Number of moles = $\frac {1.505 \times 10^{23}}{6.023 \times 10^{23}}$

= 0.25 mol

Thus, the moles of sugar present in the sample is 0.25 mol.

6 0

3 years ago

Read 2 more answers

Consider the following equilibrium:

Veseljchak [2.6K]

Answer:

Explanation:

Buffer has equal concentrations of A- and HA.

B. when [F -] is equal to [HF]

3 0

3 years ago

Read 2 more answers

Carry out the following calculation, paying special attention to the significant figures (where 4/3 is exact), rounding, and uni

babunello [35]

Answer:

Value = 1.80 g/cm³ (Approx)

Explanation:

Given:

$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3}$

Computation:

$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3} \\\\\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)} \\\\ \frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)}\\\\ \frac{3.39 \times 10^7g}{18.8166132\times 10^6 cm^3} \\\\ 1.80159945g/cm^3$

Value = 1.80 g/cm³ (Approx)

7 0

4 years ago

If eggs are so fragile, how do they actually protect the growing bird?

Step2247 [10]

Although birds' eggs appear to be fragile, they are in fact extremely robust. The oval shape applies the same rules of engineering as an arched bridge; the convex surface can withstand considerable pressure without breaking.

6 0

4 years ago