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3 years ago

What must happen before a body cell can begin mitotic cell division

1 answer:

5 0

Prophase is the first stage of Mitosis and also the beginning stage in which the cell prepares itself to begin to other stages of Mitosis.

Hope this helps!!!

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A 1.00 g sample of a metal X (that is known to form X ions in solution) was added to 127.9 mL of 0.5000 M sulfuric acid. After a

Semenov [28]

Answer: The metal having molar mass equal to 26.95 g/mol is Aluminium

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of NaOH solution = 0.5000 M

Volume of solution = 0.03340 L

Putting values in equation 1, we get:

$0.5000M=\frac{\text{Moles of NaOH}}{0.03340L}\\\\\text{Moles of NaOH}=(0.5000mol/L\times 0.03340L)=0.01670mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, 0.01670 moles of NaOH will react with = $\frac{1}{2}\times 0.01670=0.00835mol$ of sulfuric acid

Excess moles of sulfuric acid = 0.00835 moles

Calculating the moles of sulfuric acid by using equation 1, we get:

Molarity of sulfuric acid solution = 0.5000 M

Volume of solution = 127.9 mL = 0.1279 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.5000M=\frac{\text{Moles of }H_2SO_4}{0.1279L}\\\\\text{Moles of }H_2SO_4=(0.5000mol/L\times 0.1279L)=0.06395mol$

Number of moles of sulfuric acid reacted = 0.06395 - 0.00835 = 0.0556 moles

The chemical equation for the reaction of metal (forming $M^{3+}$ ion) and sulfuric acid follows:

$2X+3H_2SO_4\rightarrow X_2(SO_4)_3+3H_2$

By Stoichiometry of the reaction:

3 moles of sulfuric acid reacts with 2 moles of metal

So, 0.0556 moles of sulfuric acid will react with = $\frac{2}{3}\times 0.0556=0.0371mol$ of metal

To calculate the molar mass of metal for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Mass of metal = 1.00 g

Moles of metal = 0.0371 moles

Putting values in above equation, we get:

$0.0371mol=\frac{1.00g}{\text{Molar mass of metal}}\\\\\text{Molar mass of metal}=\frac{1.00g}{0.0371mol}=26.95g/mol$

Hence, the metal having molar mass equal to 26.95 g/mol is Aluminium

6 0

3 years ago

H2O2 is a polyatomic ion ?

Bogdan [553]

Answer:

If you are meaning O2^2- ion, well, don’t forget that ions have a charge, that has to be specified when referring to them. It is a polyatomic ion just because it consists of more than one atom, irrespective of the fact that these atoms are of the same element or not. It was given that name because at the early times chemistry was founded as a science, it was found that with respect to other oxygenated substances, peroxides contained more oxygen than expected: Latin prefix per- gives the terms it is attached to the meaning of being increased, enhanced, and similar.

Explanation:

3 0

3 years ago

If an atom has 3 protons, what is its atomic number?

Andru [333]

Answer:

Atomic Number = 3.

Explanation:

The number of protons determines the atomic number. Basically the number of protons is the exact same as the atomic number.

Protons 3 = Atomic number 3

5 0

3 years ago

Where would you have to be to see the view shown above? Explain.

Ahat [919]

In front of a telescope or on the moon

5 0

3 years ago

13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid?

Phoenix [80]

Answer:

1.02mole

Explanation:

The reaction equation is given as:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

Given:

Mass of H₂SO₄ = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16) = 98g/mol

Now;

Number of moles = $\frac{50}{98}$ = 0.51mole

From the balanced reaction equation:

1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51 = 1.02mole of NaOH

6 0

3 years ago