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Soloha48 [4]
2 years ago
9

Round your answer to the nearest hundredth.

Mathematics
1 answer:
kondor19780726 [428]2 years ago
7 0

Answer:

000.212

Step-by-step explanation:

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-a(n)=-5+6(n-1) find the 12th term
mamaluj [8]

Answer:

  61

Step-by-step explanation:

Put 12 where n is, then do the arithmetic.

  a(12) = -5 +6(12-1) = 61

_____

We assume you didn't really mean to show an equation for -a(n). If you did, then the term you want is -61.

8 0
3 years ago
If there are 3 people in a room, the probability that they all have the same birthday is
Nostrana [21]
There is .82% chance they will have the same bdays
7 0
3 years ago
Apply the distributive property to factor out the greatest common factor. 44h-33=
Flauer [41]

Answer:

11(4h-3)

Step-by-step explanation:

The greatest known common factor of 44h and 33 is 11. So using the distributive property, I got 11(4h-3)

8 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Help me I have no idea how to do 18
sleet_krkn [62]

First, subtract px2 from both sides.

Now you have:

x3 - px2 = (1 - p) x1

Next, divide both sides by (1 - p)

So now you have

x3 - px2/(1 - p) = x1

...as your final answer


*You can decide if you want to leave the parenthesis in your final answer, I left them there so it could be visible where I put them. :)

5 0
3 years ago
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