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Vinvika [58]
3 years ago
4

A sensor mounted to a cantilever beam indicates beam motion with time. When the beam is deflected and released (step test), the

sensor signal indicates that the beam oscillates as an underdamped second-order system with a ringing frequency of 10 rad/s. The maximum displacement amplitudes are measured at three different times corresponding to the 1st, 16th, and 32nd cycles and found to be 17, 9, and 5 mV, respectively. Estimate the damping ratio and natural frequency of the beam based on this measured signal, K

Physics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

The damping ratio= 2.93 × 10^-3 and the natural frequency is 10rad/s

Explanation:

Check attachment

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Why are there warnings about using your cell phone while pumping gas?
kompoz [17]

There are warnings about using your cell phone while pumping gas because cell phone batteries can explode.

<h3>What is pumping gas?</h3>

When the vehicle is not having enough fuel to drive more miles, it needs to be fueled by petrol, diesel or natural gas. This is called pumping gas.

According to the rules of National Fire Protection Association, No one is allowed to use any type of electronic items while pumping gas. So, the cell phone is not allowed.

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Thus, there are warnings about using your cell phone while pumping gas because cell phone batteries can explode.

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4 0
2 years ago
What is the frequency of an electromagnetic wave that has a wavelength of 4,000m?
NeTakaya

Answer:

f=75000hz

Explanation:

fλ= c

f= c/λ

f = 3.0×10^8/4000

f=75000hz

7 0
4 years ago
A 1.00 -kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Fig. P8.62a). The object has
LekaFEV [45]

The distance D where the object comes to rest is 1.08.m.

<h3>What is the distance?</h3>
  • The separation of one thing from another in space; the distance or separation in space between two objects, points, lines, etc.; remoteness. The distance of seven miles cannot be accomplished in one hour of walking.
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(c) the distance D where the object comes to rest.

W_{total} =ΔKE ⇒ -0.25*1*9.8*D = 0-1/2*1*2.3^{2}

⇒D=\frac{0.5*2.3^{2} }{2.45}

⇒1.08.m

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5 0
2 years ago
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a batte
VikaD [51]

Answer:

R_3 < R_1 < R_2

Explanation:

The resistance of a wire is given by:

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

1) The first wire has length L and cross-sectional area A. So, its resistance is:

R_1=\frac{\rho L}{A}

2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is

R_2=\frac{2\rho L}{A}

3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is

R_3=\frac{\rho L}{2A}

By comparing the three expressions, we find

R_3 < R_1 < R_2

So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).

5 0
3 years ago
A helicopter descends from a height of 600 m with uniform negative acceleration, reaching the ground at rest in 5.00 minutes. de
uranmaximum [27]
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.

Let a =  the acceleration of descent., m/s².
Let u =  initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u,  v, and a are measured as positive upward.

Then
 u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a                  (1)

Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600       (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²

From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s

Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.

3 0
3 years ago
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