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Gekata [30.6K]
3 years ago
13

Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?

Physics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

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If a person walks 3 m north and 5 meters east, how would you find the displacement for that person? what would the displacement
UkoKoshka [18]

Answer:

AC)=(AB)2+(BC)2−−−−−−−−−−−−√=42+32−−−−−−√

⇒displacement=16+9−−−−−√=25−−√=5m

8 0
3 years ago
Consider two identical objects of mass m = 0.250 kg and charge q = 4.00 μC. The first charge is held in place at the origin of a
Gnom [1K]

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

8 0
3 years ago
A change in position of an object relating to time
MaRussiya [10]
The answer is: Motion!

Have a great day
3 0
3 years ago
Read 2 more answers
Suppose a current flows through a copper wire. Which two things occur?
worty [1.4K]
I’m pretty sure the answer is c and d hope this helps and good luck
3 0
3 years ago
Read 2 more answers
3. Suppose that you have an electrically charged stick. If you divide the stick in half, each half will have half the original c
FrozenT [24]

Answer:

No, you can't keep on dividing the charge forever.

Explanation:

No, you can't keep on dividing the charge in that manner forever because the total charge of the stick is an integer multiples of individual units known as an elementary charge, <em>which is the electron (e) charge (e = 1.602x10⁻¹⁹C)</em>.

Therefore the limit of the division of the original charge will be the electron charge since it is the smallest charge that can exist freely.  

I hope it helps you!  

8 0
3 years ago
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