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Gekata [30.6K]
3 years ago
13

Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?

Physics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu
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d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge q_{1} between the two charges.

q_{1} = magnitude of charge on one charge

q_{2} = magnitude of charge on other charge

q_{1} = 3 q_{2}

E_{1} = Electric field by charge q_{1} at point "a"

E_{2} = Electric field by charge q_{2} at point "a"


Electric field by charge q_{1} at point "a" is given as

E_{1} = kq_{1} /r²

Electric field by charge q_{2} at point "a" is given as

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E_{2} = E_{1}

kq_{2} /(d-r)² = kq_{1} /r²

q_{2} /(d-r)² = 3q_{2} /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm


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