All categories

2 years ago

Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?

Physics

1 answer:

alekssr [168]2 years ago

7 0

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

You might be interested in

A Lemon falls off a blimp and hits the ground 14 seconds later. How fast was it moving before it hits the ground?

Luda [366]

Answer: Lemon blossoms falling off a potted lemon tree may also be caused by cool drafts, as well as under or over watering. A lemon tree dropping flowers may be a sign of drought or other changes in watering. When water is scarce, a lemon tree will drop flowers or fruit to conserve energy. Flooding, waterlogged soil or over-watering can also cause ...

Explanation:

5 0

3 years ago

Why are citizens obligated to respond to such documents?

Zina [86]

To protect the constitutional right to confront ones accused

5 0

2 years ago

The main purpose of a service panel in a house is to A. keep the meter working correctly. B. connect the service drop to the hou

cricket20 [7]

I think the best answer would be the last option. The main purpose of a service panel in a house is to keep electrical hazards localized. Service panels are used to identify circuit loads and isolate these loads so when you want to check the equipment you can easily identify the line. Also, it would serve as the isolation point to avoid any electrical hazards.

3 0

3 years ago

Read 2 more answers

A boy can swim 3.0 meter a second in still water while trying to swim directly across a river from west to east, he is pulled by

lana66690 [7]

Answer:

Angle: $48.19^o$

Explanation:

<u>Two-Dimension Motion</u>

When the object is moving in one plane, the velocity, acceleration, and displacement are vectors. Apart from the magnitudes, we also need to find the direction, often expressed as an angle respect to some reference.

Our boy can swim at 3 m/s from west to east in still water and the river he's attempting to cross interacts with him at 2 m/s southwards. The boy will move east and south and will reach the other shore at a certain distance to the south from where he started. It happens because there is a vertical component of his velocity that is not compensated.

To compensate for the vertical component of the boy's speed, he only has to swim at a certain angle east of the north (respect to the shoreline). The goal is to make the boy's y component of his velocity equal to the velocity of the river. The vertical component of the boy's velocity is

$v_b\ cos\alpha$

where $v_b$ is the speed of the boy in still water and $\alpha$ is the angle respect to the shoreline. If the river flows at speed $v_s$ , we now set

$v_b\ cos\alpha=v_s$

$\displaystyle cos\alpha=\frac{v_s}{v_b}=\frac{2}{3}$

$\alpha=48.19^o$

8 0

2 years ago

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 38 ft/s2. what is the dist

e-lub [12.9K]

Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.

So now we show it > $38 \frac{ft}{s^2} x \frac{1mi}{5280ft} x \frac{(3600s)^2}{(1h)^2} = 93272.27 \frac{mi}{h^2}$

Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.

Which the formula for constant acceleration would be > $v_2^2=v_1^2 + 2as$

The initial velocity is 50mi/h $(v_1=50)$

When it stops the final velocity is $(v_2=0)$

Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27

Then we substitute the values in....

$0^2 = 50^2 + 2(-93272.27)s

0 = 2500 - 186544.54s

Isolate S next.

185644.54s= 2500

s = 2500/(185644.54)

s=0.0134
$

So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards > $0.0134 mi * \frac{5280ft}{1mi} = 70.8 ft$
So this means that the car traveled in feet 70.8 ft before it came to a stop.

4 0

2 years ago