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nikklg [1K]
3 years ago
8

an 11 pound bowling ball has a circumference of 27 inches. calculate the density of the bowling ball and determine whether it wi

ll float or sink if placed in water. ignore the holes in the bowling ball
Chemistry
1 answer:
notsponge [240]3 years ago
4 0

Answer:

The density is 0.0036023 pounds/inches³, which is 99.71 kg/ m³. The ball will float.

Explanation:

Density is mass/ volume.

The mass is 11 pounds.

Calculate the volume of a sphere by using \frac{4}{3}πr².

V =\frac{4}{3}π(27)²

V = 3053.63 inches³

Density = mass/volume

Density = 11 pounds/ 3053.63 inches³

Density = 0.0036023 pounds/inches³

Convert this to kg/ m³, which is 99.71 kg/ m³. Water has a density of 1000 kg/m³. Since the ball has a lower density than water, it will float

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A chemist prepares a solution of aluminum sulfate Al2SO43 by weighing out 101.g of aluminum sulfate into a 200.mL volumetric fla
qaws [65]

Answer:

50.5 g/dL

Explanation:

From the question given above, the following data were obtained:

Mass of Al₂(SO₄)₃ = 101 g

Volume (V) = 200 mL

Concentration of solution (g/dL) =?

Next, we shall convert 200 mL to decilitre (dL).

This is illustrated below:

1 mL = 0.01 dL

Therefore,

200 mL = 200 mL / 1 mL × 0.01 dL

200 mL = 2 dL

Therefore, 200 mL is equivalent to 2 dL.

Finally, we shall determine the concentration of the solution in g/dL as follow:

Mass of Al₂(SO₄)₃ = 101 g

Volume (V) = 2 dL

Concentration of solution (g/dL) =?

Concentration of solution (g/dL) = mass /volume

Concentration of solution (g/dL) = 101/2

= 50.5 g/dL

Therefore, the concentration of the Al₂(SO₄)₃ solution is 50.5 g/dL

8 0
4 years ago
What are all four Quantum numbers of 11th electron of magnesium​
ruslelena [56]

Answer:n=0

l=0

ml=0

ms = =1/2 or +1/2

Explanation:

3 0
3 years ago
A solid was found to be highly soluble in water. Treating separate portions of a solution of this solid with aqueous solutions o
chubhunter [2.5K]

Answer:

c. Li_2CO_3

Explanation:

Hello,

Due to the fact that an odorless gas was released, the chemical reaction between lithium carbonate and a random acid (for instance hydrochloric acid) turns out into:

Li_2CO_3(s)+2HCl(aq)-->2LiCl(aq)+CO_2(g)+H_2O(l)

It is known that carbonic acid is unstable and it quickly decomposes into water and carbon dioxide which is an odorless gas. In spite of the fact that the PbSO_3 releases SO_2 it isn't the solid since that gas is odorous.

Best regards.

3 0
3 years ago
If you place an item that is 2g/cm3 in a glass of water, will the object float or sink?
Phantasy [73]
It will sink in that glass of water.
as, it's density is more than density of water.

you might be known that the density of water is 1g/cm^2 and it's given that the density of the item is 2g/cm^2,
and
An object only floats in water if it's density is less than that of water so,
that item is going to sink.
8 0
3 years ago
Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.
tensa zangetsu [6.8K]

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.25 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}

(\alpha)=0.0084

[H^+]=c\times \alpha

[H^+]=0.25\times 0.0084=0.0021

Also pH=-log[H^+]

pH=-log[0.0021]=2.7

Thus pH is 2.7

5 0
3 years ago
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