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NeX [460]
3 years ago
13

Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.25 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}

(\alpha)=0.0084

[H^+]=c\times \alpha

[H^+]=0.25\times 0.0084=0.0021

Also pH=-log[H^+]

pH=-log[0.0021]=2.7

Thus pH is 2.7

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