1 mole of butane uses 4.5 moles of oxygen
0.1 mole of butane will use = 0.1 * 4.5 = 0.45 moles
P = 100 kPa = 100,000Pa
n = 0.45
T = 295 K
V = ?
Using PV = nRT
⇒ 100,000 * V = 0.45 * 8.314 * 295
⇒100,000 V = 1103.68
⇒ V = 1103.68/100,000 m³
⇒ V = 1103.68/100,000 * 1000 dm³
⇒ V = 11.036 dm³
You need 11.036 dm³ oxygen.
Explanation:
Each orbital within a particular sublevel is distinguished by its value of ml. This quantum number may be more aptly named the orbital orientation quantum number. In each energy sublevel (designated by l) there are 2l+1 possible independent orientations of the electron cloud.
Answer:
1 and 3 i think so i could be wrong