Answer:
101.50 g H₂O
Explanation:
The mole ratio of HNO₃ and H₂O is 6 : 2
Hence, 16.9 moles of HNO₃ will produce = 2/6×16.9 = 5.63 moles of H₂O
Also,
Mass = Moles × M.Mass
Mass = 5.63 mol × 18.02 g/mol
Mass = 101.50 g H₂O
Answer:
4
Explanation:
The zeros before a non zero digit do not count as significant figures so there are 4 sig figs in the number
During the reaction of glucose and fructose with excess phenylhydrazine to form osazone, only the C-1andC-2 atoms of glucose and fructose participate in the reaction. The rest of the molecule remains intact. Hence, glucose and fructose produce the same osazone.
Answer:
Question: What Is The Correct IUPAC Name For S2F8? X ( ( (I) (IV) Di- Mono- Penta- Tetra- Tri- Hepta- Octa- Hexa- Fluorine Selenide Flourate Sulfide Sodium Sulfate Sulfur Fluoride Hydrate Acid.
Answer:
Mass of chemical = 1.5 mg
Explanation:
Step 1: First calculate the concentration of the stock solution required to make the final solution.
Using C1V1 = C2V2
C1 = concentration of the stock solution; V1 = volume of stock solution; C2 = concentration of final solution; V2 = volume of final solution
C1 = C2V2/V1
C1 = (6 * 25)/ 0.1
C1 = 1500 ng/μL = 1.5 μg/μL
Step 2: Mass of chemical added:
Mass of sample = concentration * volume
Concentration of stock = 1.5 μg/μL; volume of stock = 10 mL = 10^6 μL
Mass of stock = 1.5 μg/μL * 10^6 μL = 1.5 * 10^6 μg = 1.5 mg
Therefore, mass of sample = 1.5 mg
