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Daniel [21]
4 years ago
15

A car traveled at an average speed of 35 mph for 5 hours. How far did it travel?

Physics
2 answers:
zaharov [31]4 years ago
8 0

Hello, Thanks for asking your question on brainly!

To solve this problem we will use the formula S/T=D or Speed/Time=Distance.

This problem wants us to find how far he traveled(The distance)

Now to plug in the formula.

35mph/5hr=?

35/5=7

So the car traveled 7 km


Hope this helps, Have a great day.

goblinko [34]4 years ago
3 0

Answer:

Distance, d = 175 miles

Explanation:

It is given that,

Average speed of the car, v = 35 mph

Time taken, t = 5 h

To find,

Distance covered by the car.

Solution,

The product of velocity and time is called the distance covered by it. Its expression is given by :

d=v\times t

d=35\ mph\times 5\ h

d = 175 miles

So, the distance covered by the car is 175 miles. Hence, this is the required solution.

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A 200 N trash can is pulled across the sidewalk by a person at constant speed by a force of 75 N. What is the coefficient of fri
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Answer:

μ = 0.375

Explanation:

F = Applied force on the trash can = 75 N

W = weight of the trash can = 200 N

f = frictional force acting on trash can

Since the trash can moves at constant speed, force equation for the motion of can is given as

F - f = 0

75 - f = 0

f = 75 N

μ = Coefficient of friction

frictional force is given as

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5 0
3 years ago
An airplane is moving at 350 km/hr. If a bomb is
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Answers:

a) -171.402 m/s  

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_{o}+V_{oy}t-\frac{1}{2}gt^{2} (1)

x=V_{ox}t (2)

V_{f}=V_{oy}-gt (3)

Where:

y=0 m is the bomb's final height

y_{o}=1.5 km \frac{1000 m}{1 km}=1500 m is the bomb's initial height

V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the bomb's range

V_{ox}=350 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=97.22 m/s is the bomb's initial horizontal velocity

V_{f} is the bomb's final velocity

Knowing this, let's begin with the answers:

<h3>b) Time </h3>

With the conditions given above, equation (1) is now written as:

y_{o}=\frac{1}{2}gt^{2} (4)

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

t=\sqrt{\frac{2 (1500 m)}{9.8 m/s^{2}}} (6)

t=17.49 s (7)

<h3>a) Final velocity </h3>

Since V_{oy}=0 m/s, equation (3) is written as:

V_{f}=-gt (8)

V_{f}=-(97.22)(17.49 s) (9)

V_{f}=-171.402 m/s (10) The negative sign only indicates the direction is downwards

<h3>c) Range </h3>

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

5 0
3 years ago
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Answer:

They sh0uld g0 t0 the reactor and then, see what the issue is...

Explanation:

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Is there gravity in water?
Alexus [3.1K]

Answer: Yes.

Explanation:

There is gravity in water because How does the water go up in the cycle? the garavity with the wind pull it up.

3 0
3 years ago
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A baseball player hits a baseball with a bat. The mass of the ball is 0.25 kg. The ball accelerates at 200 m/s2. What is the for
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Answer:

50N

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Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

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