Answer:
The speed of the wave on the longer wire is 580m/s
Explanation:
The velocity possessed by a stretched string is directly proportional to the tension in the string and inversely proportional to the mass per unit length of the string. Mathematically,
V = √T/m
Where V is the velocity of wave in the wire
T is the tension in the wire
M is the mass per unit length of the wire
Let m1 and m2 be the mass per unit length of the wires
Let T1 and T2 be their respective tensions
Since the tension and mass of the wire is the same
m1= m2= m.
T1=T2=T
Let m1 =M/l
m2 =M/4l( since the second is tour times as far apart)
V1 = 290m/s(velocity in shorter wire)
V2 is the velocity of the longer wire.
V1 = √T/(m/l)
290 = √Tl/m
290² = Tl/m... 1
V2 = √4Tl/m
V2²= 4Tl/m... 2
Dividing equation 1 by 2 we have;
290²/V2² = {Tl/m}/{4Tl/m}
290²/V2² = Tl/m × m/4Tl
290²/V2² = 1/4
Cross multiplying we have;
V2² = 290²×4
V2 = √290²×4
V2 = 290×2
V2 = 580m/s
Answer:
The light wave could be reflected by the object
Baseball, javelin, and maybe the clock but not sure on that... Just say baseball and javelin
Yes, you can chemically change or alter DNA
Answer:
Displacement: 2.230 km Average velocity: 1.274
Explanation:
Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:
- 0.916 km due east is an horizontal direction and cane be seen as direction towards the negative side of X-axis.
- 0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
- 3.52 km in a direction of 49.7° has components on X and Y axes. It is necessary to break it down using trigonometry,
First of all. We need to sum all the X components and all the Y componets.
∑
⇒ ∑![Sx = [tex]3.52cos(49.7) - 0.916](https://tex.z-dn.net/?f=Sx%20%3D%20%5Btex%5D3.52cos%2849.7%29%20-%200.916)
∑
∑
⇒ ∑
∑
The total displacement is calculated using Pythagoeran therorem:
⇒
With displacement calculated, we can find the average speed as follows:
⇒ 
