Question

A 0.140-kg baseball is pitched horizontally at 33.6 m/s. When a player hits the ball, it moves at the

Answer 1

Answer:

F = 1176 N

Explanation:

Given that,

Mass of a baseball, m = 0.140-kg

Initial speed of the baseball, u = 33.6 m/s

Final speed of the baseball, v = -33.6 m/s (in opposite direction)

The time of contact of the bat and the ball, t = 0.008 s

We need to find the  average force the bat exerts on the ball. The force acting on the ball is given by :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.14(-33.6-33.6)}{0.008}\\F= -1176\ N$

So, the average force the bat exerts on the ball is 1176 N.