A 0.140-kg baseball is pitched horizontally at 33.6 m/s. When a player hits the ball, it moves at the
1 answer:
Answer:
F = 1176 N
Explanation:
Given that,
Mass of a baseball, m = 0.140-kg
Initial speed of the baseball, u = 33.6 m/s
Final speed of the baseball, v = -33.6 m/s (in opposite direction)
The time of contact of the bat and the ball, t = 0.008 s
We need to find the average force the bat exerts on the ball. The force acting on the ball is given by :
So, the average force the bat exerts on the ball is 1176 N.
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Answer:
Wavelength of wave is 2.5 meters
Explanation:
Given that,
Speed of a wave, v = 350 m/s
Frequency of the wave, f = 140 Hz
The formula to find the speed of sound is given by :
The speed of sound is more in higher temperature. At higher temperature, the molecules vibrate with more energy. As a result, sound travel faster in a warm room.
Answer:
7.9060 m²
8.57 Volts
5.142×10⁻⁶ Joule
1.2×10⁻⁶ Coulomb
Explanation:
C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F
d = Distance between plates = 0.5 mm = 0.5×10⁻³ m
Q = Charge = 1.2 μC = 1.2×10⁻⁶ C
ε₀ = Permittivity = 8.854×10⁻¹² F/m
Capacitance
∴ Area of each plate is 7.9060 m²
Voltage
∴ Potential difference between the plates if the capacitor is charged to 1.2 μC is 8.57 Volts.
Energy stored
E=0.5CV²
⇒E = 0.5×0.14×10⁻⁶×8.57²
⇒E = 5.142×10⁻⁶ Joule
∴ Stored energy is 5.142×10⁻⁶ Joule
Charge
Q = CV
⇒Q = 0.14×10⁻⁶×8.57
⇒Q = 1.2×10⁻⁶ C
∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb