Answer:
a) total moment of inertia is 1359.05 kg m^2
b) angular acceleratio is 0.854rad/sec^2
Explanation:
Given data:
m1=6.9 kg
L=4.88 m
m2=34.5 kg
R=1.22 m
we klnow that moment of inertia for rod is given as
J1=(1/12) ×m×L^2
moment of inertia for sphere is given as
J1=(2/5) ×m×r^2
As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R
For rod distance is d1=0.5*L
By Steiner theorem
for the rod we get
for the sphere we get
And the total moment of inertia for the first case is
b) F=476 N
The torque for system is given as
where a is angle between Force and distance d
and where d represent distance from rotating axis.
In this case a = 90 degree
M=476*2.44 = 1161.44 Nm
The acceleration is calculated as
= 0.854 rad/sec^2
Explanation:
According to the question ,
- mass = 920kg
- time = 1s
- Initial velocity = 16m/s
- Final velocity = 9.5m/s
And we need to find out ,
As we know that Force is the rate of change of momentum ,
F = ∆p/t
F = mv - mu/t
F = m(v - u)/t
F = 920(9.5-16)/1 N
F = 920 * -6.5 N
Force = -5980N
The direction of the force will be opposite to the direction of velocity of the car .
- Distance travelled while breaking ?
Using the 3rd equation of motion , we have ,
2as = v² - u²
2 (v-u)/t *s =(v+u)(v-u)
2(t)(s) = v + u
2 * 1 * s = 16 + 9.5
s = 25.5/2 m
s = 12.75 m
<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
That's <em>TRUE</em>.
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-- The Spring and Fall are opposite too.