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gizmo_the_mogwai [7]

2 years ago

10

2 spheres are made from the same material. One is smaller and one is larger. Is the smaller sphere made up of smaller atoms than

the larger sphere?

2 answers:

cluponka [151]2 years ago

8 0

Answer:

No

Explanation:

It’s just made up of less atoms.

motikmotik2 years ago

6 0

No because because they are made up of the same material so that means same size of atoms! I hope this helps

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What type of wave has particles push together and pull apart?

wariber [46]

when wave propagate through the medium the medium particles have two type of possible motions

1) Transverse Waves : here medium particles will move perpendicular to wave propagation and they pull and push perpendicular to the length

2) Longitudinal wave : here medium particles will move to and fro along the length of the medium and the medium particles will push and pull together along the length of the string.

So here in two types of wave motion it will depends on the medium type as well as it will depend on the source how is wave produced.

So the given type of wave in which particles push together and pull apart the wave must be longitudinal wave.

5 0

3 years ago

A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia

Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0

3 years ago

In a real world trampoline, how do gymnasts keep a constant bounce height

kkurt [141]

By using common factors of physics: weight, gravity, and stability.
Weight would keep them at a constant height.
Gravity helps the weight and how much force it propels the person, or objects, into the air.
Stability helps adjust how much distance the person, or object, needs to be.

7 0

3 years ago

A space walking astronaut has become detached from her spaceship.shes floating in space while holding a wrench she is thinking a

victus00 [196]

Answer:

Newton's third law of motion states that for every action, there is equal and opposite reaction.

While space walking, when the astronaut gets detached from the space ship, she floats in space holding a wrench. In order to get back to the spaceship, she should throw the wrench in the opposite direction of the spaceship. This action would cause a reaction on her own body and she would be pushed away from the wrench and towards the spaceship. Thus, she can return back to the spaceship in this way.

4 0

2 years ago

Anna Litical is practicing a centripetal force demonstration at home. She fills a bucket with water, ties it to a strong rope, a

dlinn [17]

Answer:

Explanation:

Suppose when bucket is half full it has a mass of 2 m rotating in a circle of radius r

When Bucket is quarter full then it has a mass of m rotating in a circle of radius r.

When an object moves in a circular path then it experiences an inward force which is given by

$F_1=\frac{2mv^2}{r}$

where v=velocity of bucket

Force in case 2 is given by

$F_2=\frac{mv^2}{r}$

Thus $F_1=2F_2$

therefore force required in half bucket is more than force required in quarter bucket full.

6 0

3 years ago