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3 years ago

Please help, Thanks.

Mathematics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

49x² + 28xy + 4y² ← is a perfect square of the form

(ax + by)² = a²x² + 2abxy + b²y²

49 = 7² ⇒ a = 7 and 4 = 2² ⇒ b = 2

2ab = 2 × 7 × 2 = 28

Hence

49x² + 28xy + 4y² = (7x + 2y)²

with factor 7x + 2y ⇒ C

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How do I do this? <br><br>f(a)=4a+5; Find f(2)

Mariana [72]

F(2)=4(2)+5
f(2)=8+5
f(2)=13

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3 years ago

Solve the triangle. Round your answers to the nearest tenth.

wel

Answer:

m∠A ≈ 43°

m∠B ≈ 55°

mBC ≈ 20

Step-by-step explanation:

Law of Sines: $\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Step 1: Find m∠B

$\frac{29}{sin82} =\frac{24}{sinB}$

Step 2: Solve for ∠B

29sinB = 24sin82°

sinB = 24sin82°/29

B = sin⁻¹(24sin82°/29)

B = 55.038°

Step 3: Find m∠A

180 - (55.038 + 82)

180 - 137.038

m∠A = 42.962°

Step 4: Find BC

$\frac{29}{sin82} =\frac{BC}{sin42.962}$

Step 5: Solve for BC

29sin42.962° = BCsin82°

BC = 29sin42.962°/sin82°

BC = 19.9581

4 0

3 years ago

Seven fifths of a number, z, subtracted from 6 times the same number is 3 .

Alex_Xolod [135]

6z-7z/5=3

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3 years ago

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$