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daser333 [38]
3 years ago
8

Would these two waves produce a standing wave?

Physics
2 answers:
Ganezh [65]3 years ago
6 0

Answer:

no, because the waves do not have the same amplitude

Explanation:

ivolga24 [154]3 years ago
6 0

Answer:

no, because the waves do not have the same amplitude

Explanation:

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A double insulated drill ____. A. has two ground wires to insure proper grounding B. generally has a plastic case with the elect
Len [333]

Answer:

Option B is correct.

A double insulated drill generally has a plastic case with the electrical connections and motor insulated within the tool

Explanation:

A double insulated drill's design in real life has plastic casing as the insulator & it wouldn't be a drill without its motor now, would it!?

8 0
3 years ago
Which is a unit to measure air pressure?
nata0808 [166]

Answer:

c) cubic centimetre is it's answer..

8 0
3 years ago
Read 2 more answers
Help asap
n200080 [17]

Answer:

magma

Explanation:

I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma

6 0
3 years ago
Is this the actual answer??
Nastasia [14]
It probably is the actual answer.

3 0
3 years ago
A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,
kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}

so that the <em>x</em>-component of \vec v_{\rm ave} is

\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}

and its <em>y</em>-component is

\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}

Solve for x_2 and y_2, which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.

x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}

y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}

Note that I'm reading the given details as

x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0
3 years ago
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