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lukranit [14]
3 years ago
14

Does Free Style Stroke have a 100 meter event? Yes No

Physics
2 answers:
fiasKO [112]3 years ago
8 0
Very sad to hear from her
Ray Of Light [21]3 years ago
7 0

Answer:

yes it does, your welcome

You might be interested in
Each plate of an air-filled parallel-plate capacitor has an area of 45.0 cm2, and the separation of the plates is 0.080 mm. A ba
maw [93]

Answer:

Option (e)

Explanation:

A = 45 cm^2 = 0.0045 m^2, d = 0.080 mm = 0.080 x 10^-3 m,

Energy density = 100 J/m

Let Q be the charge on the plates.

Energy density = 1/2 x ε0 x E^2

100 = 0.5 x 8.854 x 10^-12 x E^2

E = 4.75 x 10^6 V/m

V = E x d

V = 4.75 x 10^6 x 0.080 x 10^-3 = 380.22 V

C = ε0 A / d

C = 8.854 x 10^-12 x 45 x 10^-4 / (0.080 x 10^-3) = 4.98 x 10^-10 F

Q = C x V = 4.98 x 10^-10 x 380.22 = 1.9 x 10^-7 C

Q =  190 nC

3 0
3 years ago
If a 1000-pound capsule weighs only 165 pounds on the moon, how much work is done in propelling this capsule out of the moon's g
Bas_tet [7]

Answer:

  W = 1,307 10⁶ J

Explanation:

Work is the product of force by distance, in this case it is the force of gravitational attraction between the moon (M) and the capsule (m₁)

              F = G m₁ M / r²

              W = ∫ F. dr

              W = G m₁ M ∫ dr / r²

we integrate

             W = G m₁ M (-1 / r)

                 

We evaluate between the limits, lower r = R_ Moon and r = ∞

           W = -G m₁ M (1 /∞ - 1 / R_moon)

            W = G m1 M / r_moon

Body weight is

             W = mg

             m = W / g

The mass is constant, so we can find it with the initial data

For the capsule

            m = 1000/32 = 165 / g_moon

            g_moom = 165 32/1000

            .g_moon = 5.28 ft / s²

I think it is easier to follow the exercise in SI system  

           W_capsule = 1000 pound (1 kg / 2.20 pounds)

           W_capsule = 454 N

           W = m_capsule g

           m_capsule = W / g

           m = 454 /9.8

           m_capsule = 46,327 kg

Let's calculate

          W = 6.67 10⁻¹¹ 46,327   7.36 10²² / 1.74 10⁶

          W = 1,307 10⁶ J

7 0
3 years ago
Hurry help please, number 3
Dovator [93]
C most of the Earths weather occurs in this layer.
6 0
3 years ago
Read 2 more answers
You're conducting a physics experiment on another planet. You drop a rock from a height of 2.1 m and it hits the ground 0.6 seco
umka21 [38]

The formula to use is the one that connects the acceleration,
the distance fallen, and the time spent falling:

         Distance = 1/2 a T² .

You said  2.1 meters in 0.6 second .

                                                         2.1 m              = 1/2 a  (0.6 sec)²

Multiply each side by  2 :                  4.2 m              =       a (0.6 sec)²

Divide each side by (0.6 sec)² =     (4.2/0.36) m/s² =        a

                                                         a = (11 and 2/3) m/s²

                                        (about 19% more than Earth's gravity)

3 0
3 years ago
Read 2 more answers
Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.
aliina [53]

You can do this two ways:

1).  Whatever kinetic energy the rolling ball has is the amount
of energy you have to absorb in order to stop it.

2).  Whatever momentum the rolling ball has is the amount of
momentum you have to provide in the other direction to cancel it.

Since you asked about force and time, we sense 'impulse' in the
air, and we know that impulse is exactly a change in momentum.
So let's use #2 and talk about momentum and impulse.

Impulse = (force) x (time)

Momentum of a moving object is  (mass) x (speed) .


-- Momentum of the first ball:  (8 kg) x (0.2 m/s) = 1.6 kg-m/s

Impulse required to stop it = 1.6 kg-m/s

         (force) x (10 sec) = 1.6

         Force required  =  1.6 / 10  =  0.16 Newton .


-- Momentum of the second ball:  (4 kg) x (1 m/s) = 4 kg-m/s

Impulse required to stop it =  4 kg-m/s

         (force) x (10 sec) = 4

         Force required  =  4 / 10  =  0.4 Newton .

You need more force o stop the second ball.  Although its mass
is only 1/2 the mass of the 8kg ball, it's moving 5 times as fast,
and has 2.5 times the momentum of the bigger ball. 
So you need 2.5 times as much impulse to stop it.
If you're going to push on each ball for the same length of time,
then you need to push 2.5 times as hard on the smaller ball in
order to stop it.

6 0
3 years ago
Read 2 more answers
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