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3 years ago

14

Does Free Style Stroke have a 100 meter event? Yes No

2 answers:

fiasKO [112]3 years ago

8 0

Very sad to hear from her

Ray Of Light [21]3 years ago

7 0

Answer:

yes it does, your welcome

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Which of the following is a compound?<br><br> (A) Brass<br> (B) Rust<br> (C) Iron<br> (D) Steel

Naya [18.7K]

Rust is a compound of iron and oxygen.

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4 years ago

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What climate is characterized by constant high temperatures at sea level with an average temperature of 18 °C or higher, and is

kvasek [131]

Correct answer id option C that is tropical.

Tropical Climate is characterized by constant high temperature at sea level with an average temperature of 18°C or higher and is found near the equator.

Areas with tropical climate have high humidity and temperature. Countries in tropical region have high precipitation rate. Tropical climate is also known as equatorial climate. Tropical regions are found near equator. Due to high convection rate, there is abundant rainfall.

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3 years ago

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A 230.-mL sample of a 0.240 M solution is left on a hot plate overnight; the following morning, the solution is 1.75 M. What vol

Gwar [14]

Answer:

The volume of water evaporated is 199mL

Explanation:

Concentration is calculated with the following formula

$C=\frac{n}{V}$

where n is the number of moles of solute and V is the volume of the solution (in this case is the same as the solvent volume) in liters.

So we isolate the variable n to know the amount of moles, using the volume given in liters

$230mL=0.23L$

$n=C*V=0.240 M*0.23L=0.055 mol$

Now, we isolate the variable V to know the new volume with the new concentration given.

$V=\frac{n}{C} =0.055mol/1.75M=0.031L=31mL$

Finally, the volume of water evaporated is the difference between initial and final volume.

$V_{ev}= V_{i} -V_{f} =230mL-31mL=199mL$

4 0

3 years ago

An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the

Wewaii [24]

Answer:

$\frac{dB}{dt} = 3.03 \times 10^6 T/s$

Explanation:

As we know that the power emitted by the source is given as

$P = 170 W$

now we know that

$P = \frac{N}{t} (\frac{hc}{\lambda})$

now we know that energy density is given as

$u = \frac{B^2}{2\mu_0} + \frac{\epsilon_0 E^2}{2}$

now we have

$E = B c$

$u = \frac{B^2}{2\mu_0}$

intensity is defined as

$I = \frac{P}{A}$

now we have

$\frac{I}{c} = u = \frac{B^2}{2\mu_0}$ [/tex]

now we have

$\frac{dB}{dt} = \omega B$

$\frac{dB}{dt} = \frac{2\pi c B}{\lambda}$

$\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}$

here we have

$I = \frac{P}{4\pi r^2}$

$I = \frac{170}{4\pi (410)^2}$

$I = 8.05 \times 10^{-5}$

now we have

$\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}$

$\frac{dB}{dt} = 3.03 \times 10^6 T/s$

4 0

3 years ago

Match the nitrogenous base of RNA with its complement. TTACCGG TAACGCA CGCATGT TGACCTA GCCAATT ACTGGAT arrowRight GCGTACA arrowR

egoroff_w [7]

I took the test and this is the answer key showing I got it right..

Hope this helps!

3 0

3 years ago

Read 3 more answers