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Sedaia [141]
3 years ago
15

20% of the shoes in a factor are black. One shoe is chosen and replaced. A second shoe is chosen and replaced. Then a third shoe

is chosen and replaced. What is the probability that none of the shoes are black?
Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0
The probability that none of the shoes are black is 51.2%.

If 20% of the shoes are black, then 80% of the shoes are not black. To find the probability that three shoes are not black, we have to multiply 80% by itself 3 times.

0.8 x 0.8 x 0.8 = 0.512 = 51.2%
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