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tia_tia [17]
3 years ago
8

CALLING ON K12 STUDENTS... I'm in Honors Geometry and am so stuck on the end of the year Trig in Baseball assignment... Anybody

has completed it???? We can help each other...
Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0
RIP, i finished my geometry hon. EOC today, i'm in 8th :P  
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Annual rent $ 7,380
jeyben [28]

Answer:

Part A:

Rent = $7380

Mortgage payments = $9800

Insurance = $145

Taxes, insurance, maintenance = 1780+1050 = $2830

Loss of Interest on security deposit = (650*6%) = $39

Interest lost on down payment and closing cost = (4,500*6%) = $270

Growth in equity = $225

Annual appreciation = $1700

Tax savings for mortgage interest = (9,575*28%) = $2,681

Tax savings for property taxes = (1,780*28%) = $498

Total rental cost = 7,380+145+39=7,564 dollars

Total buying costs = 9,800+2,830+270-225-1,700-2,681-498=7,796 dollars

Part B:

You should consider rent because the cost of renting is less than the cost of buying.

7 0
3 years ago
This is for union and intersection. I need help.
oksano4ka [1.4K]

Problem 11) Start with set U = {1,2,3,4,5} and cross off 1,2,3 to be left with A' = {4,5}. We basically erase everything found in set A. You have the correct answer. Nice job.

Problem 12) Start with U = {1,2,3,4,5} and erase '5' to be left with {1,2,3,4}. So B' = {1,2,3,4}. You are correct here as well.

I can't help with the other problems since either letters, numbers or symbols are missing. Please make a new post and provide those updates.

6 0
3 years ago
8p + 2q = -16<br> 2p - q=2
yKpoI14uk [10]

Answer:

p = -1  q = -4

Step-by-step explanation:

a system of eq and solve for p and q ???  can do  :)

Eq. 1)  8p + 2q = - 16

Eq. 2)  2p - q = 2

use Eq .2 and solve for q

2p - 2 = q

plug into Eq.1 with q

8p +2(2p - 2) = - 16

8p +4p -4 = -16

12p = - 12

p = -1

plug -1 into Eq. 1 for p and solve for q

8(-1) + 2q = - 16

-8 + 2q = - 16

2q = -8

q = -4

8 0
3 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
What are some prime numbers?
pshichka [43]

Answer:

2,3,5,7,11

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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