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tia_tia [17]
3 years ago
8

CALLING ON K12 STUDENTS... I'm in Honors Geometry and am so stuck on the end of the year Trig in Baseball assignment... Anybody

has completed it???? We can help each other...
Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0
RIP, i finished my geometry hon. EOC today, i'm in 8th :P  
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What is the sum of the difference?
Alona [7]

Answer:

A. 9x^4 and 3x^5y

Step-by-step explanation:

there are two ways to solve this:

first way:

You can solve this my substituting numbers for x and y in this case i used 2 for x and 3 for y and see which one is equal to the original equations

the second way is the regular way

when you add or subtract numbers with variables and exponents you want to add the constants and add the exponents in this case 5x^{4} +4x^2 is the same as (5x+4x)^(4+4) = 9x^4and you can do the same process for subtraction

12x^{5}y-9x^5 y\\(12x-9x)^(5+5)*y= 3x^5y

8 0
3 years ago
Raju finished his work in 5/6 hour.Vrinda finished her work in 3/4 hour .who worked longer ? By what fraction was it longer
Nataly [62]

Answer:

Raju worked longer by 0.08 hours.

3 0
3 years ago
Plzz help me im am stuck
Pachacha [2.7K]
I hope this helps you!

7 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
The Summer Olympics were held in St. Louis 92 years before the Summer Olympics were held in Atlanta. In what year were the Olymp
andrezito [222]
1904 write if not just subtract 92 from 96 and you have your answer hope that helps
7 0
3 years ago
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