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julia-pushkina [17]
3 years ago
13

Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When car

rying 18 gallons of fuel, the airplane weighs 1999 pounds. When carrying 46 gallons of fuel, it weighs 2153 pounds. How much does the airplane weigh if it is carrying 58 gallons of fuel?
Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer:

W=2219pounds

Explanation:

If the weight  is a linear function of the amount of fuel, the following correlation is fulfilled :

\frac{2153pounds-1999pounds}{46gallons-18gallons} = \frac{W-1999pounds}{58gallons-18galons}

we solve the equation:

W=2219pounds

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A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. Wha
gtnhenbr [62]

Answer:

0.0231 m/s

Explanation:

Given the question :

A small toddler is playing in his yard. Over the course of 29.01 s, he walks 2.099 m S before turning N and walking 1.429 m. What is his average velocity?

Distance walked south = 2.099 metre

Time taken = 29.01s

Distance walked north = 1.429 metre

Average Velocity = Displacement / time

The Displacement is hence,

(2.099 m - 1.429m) = 0.67m

Average Velocity = 0.67m / 29.01s

Average Velocity = 0.02309 m/s

Average Velocity = 0.0231 m/s

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4 years ago
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3 years ago
The brakes on a 15,680 N car exert a stopping force of 640 N.
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1568 Kg is the answer

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3 years ago
A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera
Fantom [35]
In order to accelerate the dragster at a speed v_f = 100 m/s, its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
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however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is -W_f:
W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J

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And since 1 horsepower is equal to 746 W, we can rewrite the power as
P=4.08 \cdot 10^6 W \cdot  \frac{1 hp}{746 W} =547 hp



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4 years ago
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Alex_Xolod [135]

Answer:

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