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Ad libitum [116K]
2 years ago
13

The same girl in number 3 (above) pushes another friend on the same skateboard.

Physics
1 answer:
LuckyWell [14K]2 years ago
8 0

The mass of her friend is<u> </u> <u>28.57.</u>

<u />

Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.

<u>Calculation:-</u>

given;

mass = ?

acceleration = 2.1 m/s

force = 60 N

Force = mass × acceleration

 mass = force/acceleration

           = 60 /2.1

           =  <u>28.57 kg</u>

The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.

Learn more about force here:-brainly.com/question/12970081

#SPJ9

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A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary
Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

  • m = 10 kg
  • g = 9.8 m/s²
  • T = ?

Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{T=98\ N}}}

The tension in the rope is <u>98 Newtons.</u>

Greetings.

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What statement is true about a spring?
Citrus2011 [14]
A spring is felxiable
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3 years ago
Read 2 more answers
10 time 20 minus 5 and yeah that’s all i need
Gnesinka [82]

Answer:

10 \times 20 - 5 \\  \\  = 200 - 5 \\  = 195

6 0
3 years ago
A rock of mass m = 0.0450 kg is attached to one end of a string and is whirled around in a horizontal circle. If the radius of t
AleksAgata [21]

Answer:

Tension, T = 0.1429 N

Explanation:

Given that,

Mass of the rock, m = 0.0450 kg

Radius of the circle, r = 0.580 m

Angular speed, \omega=2.34\ rad/s

The tension in the string is balanced by the centripetal force acting on it. It is given by :

T=\dfrac{mv^2}{r}

Since, v=r\omega

T=\dfrac{m(r\omega)^2}{r}

T=\dfrac{0.0450\times (0.580\times 2.34)^2}{0.580}

T = 0.1429 N

So, the tension in the string is 0.1429 N. Hence, this is the required solution.

8 0
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dalvyx [7]
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if the size of a planet is relatively small it will in turn be that of a smaller area which results in the less area to be covered for gas which basically means higher presence
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