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3 years ago

PLS PLS PLS PLS PLS PLS PLS PLS PLS HELP FREE POINTS

Physics

1 answer:

Ne4ueva [31]3 years ago

3 0

Answer:

see below

Explanation:

First: Leave a couple inches of wire loose at one end and wrap most of the rest of the wire around iron u-shaped bar and make sure not to overlap the wires.

Second:Cut the wire (if needed) so that there is about a couple inches loose at the other end too.

Third: Now remove about an inch of the plastic coating from both ends of the wire and connect the one wire to one end of a battery and the other wire to the other end of the battery.

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Given that the velocity of blood pumping through the aorta is about 30 cm/s, what is the total current of the blood passing thro

TiliK225 [7]

Answer:

94.248 g/sec

Explanation:

For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:

$A_1 = \pi R^2\\\\A_1 = \pi (1)^2\\\\A_1 = 3.1416 cm^2$

And, the velocity of blood pumping is 30 cm^2

Now apply the following formula to solve the total current

$Q = \rho A_1V_1\\\\Q = (1)(3.1416)(30)\\\\$

Q = 94.248 g/sec

Basically we applied the above formula So, that the total current could come

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3 years ago

The image shows a wheel that’s wound up and released. The wheel moves up and down as shown. Identify the position of the wheel w

slega [8]

The highest point of the wheel is the position of the wheel when its potential energy is greatest.

<h3>At what position of the wheel potential energy is greatest?</h3>

The position of the wheel when its potential energy is greatest when it is at the highest point because potential energy depends on the height of an object. If the object is at more height then it has more potential energy and vice versa.

So we can conclude that the highest point of the wheel is the position of the wheel when its potential energy is greatest.

Learn more about energy here: brainly.com/question/13881533

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2 years ago

The period of a simple pendulum, defined as the time necessary for one complete oscillation, is measured in time units and is gi

Oksana_A [137]

The task is to show that the right side of the equation has units of [Time], just like the left side has.

The right side of the equation is . . . 2 π √(L/G) .

We can completely ignore the 2π since it has no units at all, so it has no effect on the units of the right side of the equation. Now the task is simply to find the units of √(L/G) .

L . . . meters

G . . . meters/sec²

(L/G) = (meters) / (meters/sec²)

(L/G) = (meters) · (sec²/meters)

(L/G) = (meters · sec²) / (meters)

(L/G) = sec²

So √(L/G) = seconds = [Time]

THAT's what we were hoping to prove, and we did it !

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3 years ago

If you lift two loads up one story, how much work do you do compared to lifting just one load up one story?

Daniel [21]